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kvasek [131]
3 years ago
11

Find the configuration of any tow​

Physics
1 answer:
Yuki888 [10]3 years ago
6 0

Answer:

<h2>Ok I choose Copper and Zinc , Here is your answer⤴️⤴️</h2><h3>Hope it's helpful for you mark me as brainlist please</h3>

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In two or more sentences describe the impact of fossil fuel combustion on the global carbon cycle. In three sentences or less ex
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For many solids<span> dissolved in liquid water, the </span>solubility increases<span> with </span>temperature<span>. The </span>increase<span> in kinetic energy that comes with </span>higher temperatures<span> allows the solvent molecules to more effectively break apart the solute molecules that are held together by intermolecular attractions.</span>
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3 years ago
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What are 3 ways an object can be charged
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Calculate how much work is required to launch a spacecraft of mass m from the surface of the earth (mass mE, radius RE) and plac
mylen [45]

To solve this problem it is necessary to apply the concepts related to the conservation of energy, through the balance between the work done and its respective transformation from the gravitational potential energy.

Mathematically the conservation of these two energies can be given through

W = U_f - U_i

Where,

W = Work

U_f = Final gravitational Potential energy

U_i = Initial gravitational Potential energy

When the spacecraft of mass m is on the surface of the earth then the energy possessed by it

U_i = \frac{-GMm}{R}

Where

M = mass of earth

m = Mass of spacecraft

R = Radius of earth

Let the spacecraft is now in an orbit whose attitude is R_{orbit} \approx R then the energy possessed by the spacecraft is

U_f = \frac{-GMm}{2R}

Work needed to put it in orbit is the difference between the above two

W = U_f - U_i

W = -GMm (\frac{1}{2R}-\frac{1}{R})

Therefore the work required to launch a spacecraft from the surface of the Eart andplace it ina circularlow earth orbit is

W = \frac{GMm}{2R}

3 0
3 years ago
The board sandwiched between two other boards shown below weighs 87.5 n. if the coefficient of friction between the boards is 0.
IRINA_888 [86]
Refer to the diagram shown below.

W = 87.5 N, the weight of the sandwiched board.
μ = 0.622, the static coefficient of friction.

From the free body diagram of the sandwiched board, obtain
2μF = W
F = W/(2μ) = 87.5/(2*0.622) = 70.34 N

Answer: 70.34 N

8 0
3 years ago
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One liter of water at 56◦C is used to make iced
Genrish500 [490]

Answer:22.6g

Explanation:

Mass of water(mw)=1liter=1000g

Final temperature=20°C

Temperature of ice=0°C

Temperature of water=56°C

Change in temperature of water=56-20=36

change in temperature of ice=20-0=20

Specific heat of water=1cal/g°C

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1000x1x36=mx79.7x20

36000=1594xm

Divide both sides by 1594

36000 ➗ 1594=1594xm ➗ 1594

22.6=m of ice

m of ice=22.6g

8 0
3 years ago
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