For many solids<span> dissolved in liquid water, the </span>solubility increases<span> with </span>temperature<span>. The </span>increase<span> in kinetic energy that comes with </span>higher temperatures<span> allows the solvent molecules to more effectively break apart the solute molecules that are held together by intermolecular attractions.</span>
<span>pile
battery
<span>power sector</span></span>
To solve this problem it is necessary to apply the concepts related to the conservation of energy, through the balance between the work done and its respective transformation from the gravitational potential energy.
Mathematically the conservation of these two energies can be given through

Where,
W = Work
Final gravitational Potential energy
Initial gravitational Potential energy
When the spacecraft of mass m is on the surface of the earth then the energy possessed by it

Where
M = mass of earth
m = Mass of spacecraft
R = Radius of earth
Let the spacecraft is now in an orbit whose attitude is
then the energy possessed by the spacecraft is

Work needed to put it in orbit is the difference between the above two


Therefore the work required to launch a spacecraft from the surface of the Eart andplace it ina circularlow earth orbit is

Refer to the diagram shown below.
W = 87.5 N, the weight of the sandwiched board.
μ = 0.622, the static coefficient of friction.
From the free body diagram of the sandwiched board, obtain
2μF = W
F = W/(2μ) = 87.5/(2*0.622) = 70.34 N
Answer: 70.34 N
Answer:22.6g
Explanation:
Mass of water(mw)=1liter=1000g
Final temperature=20°C
Temperature of ice=0°C
Temperature of water=56°C
Change in temperature of water=56-20=36
change in temperature of ice=20-0=20
Specific heat of water=1cal/g°C
Latent heat of ice=79.7cal/g
1000x1x36=mx79.7x20
36000=1594xm
Divide both sides by 1594
36000 ➗ 1594=1594xm ➗ 1594
22.6=m of ice
m of ice=22.6g