The answer is a path of destruction up to 50 miles long with destroyed trees and homes.
Tornadoes form from severe thunderstorms. Wind in the higher altitude of the storm moving at a greater velocity than wind at a lower altitude creates a vertical wind shear. The faster-moving winds aloft come from the west and create an updraft when they meet slower-moving wind close to the ground that is moving in the opposite direction. As warm surface air moves upward into the thundercloud, the rotating air creates a vortex.
The image below shows before and after damage of a tornado.
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D. A gas when vinegar and baking soda are mixed
EXTRA INFO: An exmaple of phyical change is sawing a piece of wood
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Complete Question
A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A constant wind force of magnitude 13.2 N blows from left to right. Pivot Pivot F F (a) (b) H m m L L If the mass is released from the vertical position, what maximum height above its initial position will it attain? Assume that the string does not break in the process. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.What will be the equilibrium height of the mass?
Answer:
Explanation:
From the question we are told that
Mass of ball 
Length of string 
Wind force 
Generally the equation for 
is mathematically given as
Max angle =
Generally the equation for max Height 
is mathematically given as
Generally the equation for Equilibrium Height 
is mathematically given as
Answer:
The mass of the skateboard is 1.25 kg.
Explanation:
We have,
Mass of dog, m = 5 kg
Initial speed of dog, u = 2.5 m/s
Initial speed of skateboard, u' = 0 (at rest)
The dog jumps onto the skateboard and both the dog and skateboard move with a speed of 2.00 m/s. It is the common speed of the dog +skateboard, V = 2 m/s. We need to find the mass of the skateboard. Using conservation of momentum as :
m' is mass of skateboard
So, the mass of the skateboard is 1.25 kg.
Answer:
4.33m
Explanation:
Power = work done/ time
work done = power × time =650 × 2 = 1300J
work done = force × distance
distance = work done/force
distance = 1300/300 = 4.33m
