From a standard deck of cards, what is the probability that you choose a red card and then choose a 3 assuming you replaced the
2 answers:
A standard deck of cards has 52 cards. Half of the deck has red cards and half has black cards. So the first probability would be 26/52, or 1/2 (simplified, it's half the deck).
Then you put the card back and choose a 3. There are 4 cards with the number 3 in the deck. So it's 4/52.
Then you multiply both the probabilities
26/52 x 4/52 =
= 1/26
Then you put the card back and choose a 3. There are 4 cards with the number 3 in the deck. So it's 4/52.
Then you multiply both the probabilities
26/52 x 4/52 =
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Answer:
Graph of the inequality 3y-2x>-18 is given below.
Step-by-step explanation:
We are given the inequality, 3y-2x>-18
Now, using the 'Zero Test', which states that,
After substituting the point (0,0) in the inequality, if the result is true, then the solution region is towards the origin. If the result is false, then the solution region is away from the origin'.
So, after substituting (0,0) in 3y-2x>-18, we get,
3\times 0-2\times 0>-18
i.e. 0 > -18, which is true.
Thus, the solution region is towards the origin.
Hence, the graph of the inequality 3y-2x>-18 is given below.
Answer:
a = 4 cm
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
a² + 3² = 5²
a² + 9 = 25 ( subtract 9 from both sides )
a² = 16 ( take the square root of both sides )
a = = 4