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Gre4nikov [31]
3 years ago
10

Ms. Wang and her class are selling bags of cookies to raise money for a field trip.

Mathematics
1 answer:
Delicious77 [7]3 years ago
3 0

Answer:

9 bags of candy

Step-by-step explanation:

6 cookies at 14 grams each = 84 grams meaning the remaining grams of the 140 have to be the weight of the candy which = 56 grams (140-84). To find out how much candy is in one cookie divide 56 by 6 which = 9.33333. You then divide 20 by 9.3333 which = 2.14 (rounded to nearest 10th). Since you can get just over 2 cookies worth of candy per bag you only need half the number of cookies in bags of candy (9 bags)

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Use the discriminant to describe the roots of each equation. Then select the best description. 2m2 + 3 = m double root real and
Jlenok [28]

Answer:

The roots of the equation 2m²+3=m are non-real roots.

Step-by-step explanation:

Given equation:

2m²+3=m

2m²-m+3=0

Here, from the equation we can obtain the following values:

a = 2, b = -1, c = 3

Discriminant of an equation is given as:

D = b²-4ac

= (-1)²-4(2)(3)

= 1 - 21

= -20

Discriminant can tell what kinds of roots the equation have.

In our case, the discriminant is less than 0.

When D < 0, the roots of the equation are complex conjugates.(non-real)

8 0
3 years ago
Read 2 more answers
Find out if the 3 positions are on the same line or not (3,2,0) (1, -1,2) (5,5, 2)
sattari [20]

Answer:

The three positions are not on the same line.

Step-by-step explanation:

We have three points: A:(3,2,0),  B:(1,-1,2) and C:(5,5,2).

Let's build a vector that goes from one point to another; that vector will be the director of a line (if we draw a vector that goes from A to B, that vector will be the direction of the line that pass by A and B because it does not change). In order to build that vector, let's subtract B from A:

A-B=(3,2,0)-(1,-1,2)=(2,3,-2)

The equation of a line is:

p=p_0+rt

Where p is every singular point of the line, p_0 is a particular point of the line (any that we are sure that it is on the line), r is the director vector and t is the independent variable.

Now we have the director vector: (2,3,-2), and we can verify that A and B are on the line:

p=p_0+(2,3,-2)t

Because there is a value for t that satisfies both A and B: If we do p_0=(3,2,0) and t=0, we are going to obtain the point p=A; and if we do t=-1, we are going to obtain p=B. Let's see that:

p=(3,2,0)+(2,3,-2)*0=(3,2,0)\\p=A\\p=(3,2,0)+(2,3,-2)*-1=(1,-1,2)\\p=B\\

If C is also in the same line, C must accomplish the equation: p=(3,2,0)+(2,3,-2)t, so:

C=(5,5,2)=(3,2,0)+(2,3,-2)t

Let's simplify the equation writing the parametric equation, which is just to write the equation for each dimension:

5=3+2t\\5=2-3t\\2=-2t\\

You can verify that there is not a value of t that satisfies all three equations, so, the point C is not on the same line as A and B; which means that A, B and C are not on the same line.

8 0
3 years ago
Can someone please help me with these math problems ASAP?!<br> Thanks in advance! ;)
Mamont248 [21]

Answer:

11) Here given Function,

f(x) = \sqrt{2x-11}

And, g(x) = -|0.1|x+5

For f(x) = g(x)

\sqrt{2x-11}=-|0.1|x+5

2x-11=(-|0.1|x+5)^2

2x-11=0.01x^2 - 10|0.1|x+25

2x=0.01x^2 - 10|0.1|x+25+11

2x=0.01x^2 - 10|0.1|x+36

0.01x^2 - 10|0.1|x - 2x+36=0

When we solve this equation,

We found,

 x = 12.5227 ≈ 12.53

Thus, the required solution is, x = 12.53

12) Here the height of rocket A in x second,

f(x) = -16x^2+74x+9

And, The height gain by the rocket B in x seconds,

g(x) = -16x^2+82x

If at x seconds both A and B gain the same height,

That is, f(x) = g(x)

⇒ -16x^2+74x+9= -16x^2+82x

⇒74x + 9 = 82x

⇒ 82x - 74x = 9

⇒ 8x = 9

⇒ x = 1.125 ≈ 1.13

Thus, the required solution is x = 1.13 seconds (approx)


4 0
3 years ago
3 1/7 x 2 2/8 (multiply fractions)
k0ka [10]

Answer:

.214 if it is to 3 decimal places.

5 0
3 years ago
Plssss help what is x
makvit [3.9K]

Answer:

x = 4

Step-by-step explanation:

If you do not want to read the explanation go the the next part in bold

Ok so the shorter leg of the triangle is a radius of the circle. ( This is indicated by the point in the middle of the circle.) for the hypotenuse we are given one part of the length (2) The other part also happens to be a radius ( remember that a radius is a line that starts from the center of the triangle to any point of the circumference. ) Also remember that the radius is equal to 3. That being said the hypotenuse = 2+3 which equals 5.  

This triangle then happens to be a right triangle. ( A triangle formed by a tangent line and a radius is a right triangle.) This means that we can use the Pythagorean theorem to solve for x.

Below here is where the work is shown

a² + b² = c². where a and b = legs and c = hypotenuse. We are given the hypotenuse (5) and a leg (3) So we plug in what we are given and solve for the missing information. 5² = 3² + b²  

5² = 25

3² = 9

we would then have 25 = 9 + b²

Next we subtract 9 from each side

25 - 9 = 16

9 - 9 cancels out

Now we have 16 = b²

finally we want to get rid of the ²

To do so we take the square root of each side

\sqrt{16}=4\\\sqrt{b^2}=b\\b = 4

we're left with b = 4 which means that x = 4

8 0
3 years ago
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