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sveta [45]
3 years ago
9

A skateboarder is inside of a half-pipe, shown here. Explain her energy transformations as she jumps off at point A, slides to p

oint B, and finally reaches point C.

Chemistry
1 answer:
11Alexandr11 [23.1K]3 years ago
8 0

Answer:

------ At point A, the skateboarder’s energy is all potential since she is high up (PE = mgh), and gravity has the potential to pull her down. She isn't moving, so she doesn't have velocity. Therefore, she doesn't have kinetic energy. At point B, she is moving the fastest during her ride and is as close to the ground as the ramp allows. Thus, her potential energy has been turned into kinetic energy due to her velocity and lack of height. At point C, if she comes to a stop on the other side of the half-pipe, her kinetic energy has been turned back into potential energy since she is high up again.

------- Eventually, the friction between the wheels and the ground will cause the skateboard to stop. Each time she goes back and forth, she will lose some of her initial energy from her drop-in, as long as she doesn't push off the sides at all.

Explanation:

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wolverine [178]

Answer:

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Explanation:

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3 years ago
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How many moles of oxygen atoms are in 7.9E-1 moles of CO_2
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Answer:

The number of moles of O atom in (7.9\times10^{-1}) mol of CO_{2} = 1.6

Explanation:

1 molecule of CO_{2} contains 2 atoms of O

So, (6.023\times 10^{23}) molecules of  CO_{2} contains (2\times6.023\times10^{23}) atoms of O.

We know that 1 mol of an atom/molecule/ion represents 6.023\times10^{23} numbers of atoms/molecules/ions respectively.

So, (6.023\times 10^{23}) molecules of  CO_{2} is equal to 1 mol of CO_{2}.

(2\times6.023\times10^{23}) atoms of O is equal to 2 moles of O atom.

Hence, 1 mol of CO_{2} contains 2 moles of O atom.

Therefore, (7.9\times10^{-1}) mol of CO_{2} contains (2\times7.9\times10^{-1}) moles of O atom or 1.6 moles of O atom.

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Explanation:

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