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snow_tiger [21]
4 years ago
10

A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 58.8 m/s^2. The acce

leration period lasts for time 8.00 s until the fuel is exhausted. After that, the rocket is in free fall. Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.80 m/s^2 .
Physics
1 answer:
jeka944 years ago
3 0

Answer:

The maximum height will be 7408.8 meters

Explanation:

final velocity = initial velocity + acceleration × time  

final velocity = 0 m/s + 58.8 m/s^2 ×6 s  

Final velocity = 352.8 m/s  

final velocity ^2 = initial velocity ^2 + 2 × acceleration × displacement  

(352.8)^2 = (0)^2 + 2×58.8 ×displacement  

Solving for displacement,

height = 1058.4 meters.  

After this, the rocket is in free fall, we can use the same equation.  

final velocity ^2 = initial velocity ^2 + 2 ×acceleration×displacement  

final velocity = 0  

0^2 = 352.8^2 + 2×(-9.8)×displacement  

displacement = 6350.4 meters  

the maximum height will be 7408.8 meters

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As fluid is forced into the lift cylinder it forces the lift piston upward. The lift cylinder is a lot wider than the pump cylinder. This means that the area of the lift piston is a lot greater than the area of the pump piston. Because Pascal's Principle guarantees that the pressure in a fluid is the same everywhere and the area that pressure is applied over is greater at the lift cylinder, the force applied by the lift cylinder must be greater. The hydraulic lift takes the long low-force motions of the pump piston and converts then into short high-force motions of the lift cylinder.

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7 0
3 years ago
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On a horizontal frictionless surface a mass M is attached to two light elastic strings both having length l and both made of the
EastWind [94]

Answer:

ω = √(2T / (mL))

Explanation:

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The x-components of the tension forces cancel each other out, so the net force is in the y direction:

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For small angles, sin θ ≈ tan θ.

∑F = -2T tan θ

∑F = -2T (Δy / L)

(b) For a spring, the restoring force is F = -kx, and the frequency is ω = √(k/m).  (This is derived by solving a second order differential equation.)

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6 0
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An object 16.8 cm tall is placed in front of a converging lens. A real image, 46 cm tall, is formed on the other side of the len
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Hence the magnification is 2.74

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Average velocity is a vector unit (i.e. includes magnitude <em>and </em>direction) calculated by working out distance ÷ time:

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