Answer:
The third drop is 0.26m
Explanation:
The drop 1 impacts at time T is given by:
T=sqrt(2h/g)
T= sqrt[(2×2.4)/9.8]
T= sqrt(4.8/9.8)
T= sqrt(0.4898)
T= 0.70seconds
4th drops starts at dT=0.70/3= 0.23seconds
The interval between the drops is 0.23seconds
Third drop will fall at t= 0.23
h=1/2gt^2
h= 1/2×9.81×(0.23)^2
h= 0.26m
A force of 43.8 N is required to stretch the spring a distance of 15.5 cm = 0.155 m, so the spring constant <em>k</em> is
43.8 N = <em>k</em> (0.155 m) ==> <em>k</em> = (43.8 N) / (0.155 m) ≈ 283 N/m
The total work done on the spring to stretch it to 15.5 cm from equilibrium is
1/2 (283 N/m) (0.155 m)² ≈ 3.39 J
The total work needed to stretch the spring to 15.5 cm + 10.4 cm = 25.9 cm = 0.259 m from equilibrium would be
1/2 (283 N/m) (0.259 m)² ≈ 9.48 J
Then the additional work needed to stretch the spring 10.4 cm further is the difference, about 6.08 J.
<span>Electrical discharge from a charged object
is your answer</span>
300 000 000 m/s in km/s
1000 m = 1km
300 000 000 m/s = 3 * 10⁸ m/s = 3 * 10⁵ *10³ m/s
= 3 * 10⁵ *10³ m/s
= 3 * 10⁵ km/s
Speed = 3 * 10⁵ km/s
Explanation:
The new volume of water = 25 ml
The old volume of water = 15 ml
The difference = 25 - 15 but what are the units?
Since the question asks for force, the units must start out as 10 mL
In water 1 mL has a mass of 1 gram, so the answer is 10 grams.
Grams are units of mass, not weight. You should convert this into newtons.
10 grams = 1/1000 = 0.01 kg
1 kg has a weight of 9.81 Newtons
0.01 kg has a weight 0.081 Newtons
If you have never seen a Newton before, then the answer is 10 grams