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sergiy2304 [10]
3 years ago
9

Selina drops a golf ball down a deep well. The ball falls with only the force of gravity acting on it. Without any air resistanc

e, as the golf ball falls into the well, its speed is:
A. constant
B. increasing
C. decreasing
D. directional
Chemistry
1 answer:
ss7ja [257]3 years ago
8 0

<u>Answer:</u>    A. constant

Without any air resistance, as the golf ball falls into the well, its speed is constant.

<u>Explanation:</u>

Given that when the ball is released,<em>there is no air resistance acting on ball. So the ball is freely falling. </em>

The only force acting on the freely falling body is the gravitational force pulling the body towards the centre of the earth.Here the only acceleration acting on the body is the <em>acceleration due to gravity.</em>

The acceleration due to gravity is 9.8 m/s^2. so through out the journey of the ball,the acceleration is 9.8 m/s^2. <em>So as the acceleration is constant, the speed is also constant.</em>

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(a) Show that the pressure exerted by a fluid P (in pascals) is given by P = hdg, where h is the column of the fluid in metres,
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B) THE DEPTH OF THE LAKE IS 0.060 m

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1. Using the general gas law, we will calculate the initial pressure of the air bubbles.

P1V1 /T1 = P2V2/T2

P1 = Unknown

T1 = 5.24 °C

T2 = 18.73 °C

P2 = 0.973 atm

V1 = V1

V2 = 6V1

P1 = P2 V2 T1 / V1 T2

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2. Calculate the depth of the lake:

             Pressure = length * density * acceleration

            length = Pressure / density * acceleration

Pressure = 1.633 atm = 1.633 * 101, 325 Nm^2 = 165, 463.725 Nm^2

Density =  1.02 g/cm3 = 1.02 * 10^3 kg/m^3

Acceleration = 9.8 m/s^2

So therefore, the length in metres is:

Length = density * acceleration / pressure

Length =  1.02 *10^3 * 9.8 / 165, 463.725  

Length = 9.996 * 10^3 / 165 463.725

Length = 0.06 m

Hence, the depth of the lake is 0.06 m

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