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quester [9]
4 years ago
8

Animals store energy by making a polymer called glycogen. which best describes the structure of glycogen?

Chemistry
2 answers:
Alika [10]4 years ago
8 0

Answer:

Glycogen is a  polymer of glucose and it has branched structure.

Explanation:

Glycogen is made up of repetitive units of glucose. IT is a polysaccharide.

The glucose molecules are bonded by glycosidic bonds.

There is a linear chain of Glucose molecules residues are linked linearly by α-1,4 glycosidic linkages. the branching starts after 10-12 glucose units by  α-1,6 glycosidic linkages.

attashe74 [19]4 years ago
4 0
A highly branched polymer of glucose 
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Calculate the number of molecules in 4.0 mol H2O.
Juliette [100K]
1 mole H2O ---------------------- 6.02x10²³ molecules
4 moles H2O---------------------  y molecules

y = 4 * 6.02x10²³

y = 2.4x10^24 molecules

answer b

hope this helps!.
7 0
3 years ago
What volume would 3.01•1023 molecules of oxygen gas occupy at STP?
frosja888 [35]
<h3>Answer:</h3>

                  Volume  = 11.2 L

<h3>Explanation:</h3>

Step 1: Calculate Moles:

                      As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Particles and Avogadro's Number is given as,

                          Number of Moles  =  Number of Particles ÷ 6.022 × 10²³

Putting values,

                          Number of Moles  =  3.01× 10²³ Particles ÷ 6.022 × 10²³

                          Number of Moles  =  0.50 Moles

Step 2: Calculate Volume:

As we know that one mole of any Ideal gas at standard temperature and pressure occupies exactly 22.4 dm³ volume.

When 1 mole gas occupies 22.4 dm³ at STP then the volume occupied by 0.50 moles of gas is calculated as,

                      = (22.4 dm³ × 0.50 moles) ÷ 1 mole

                      = 11.2 dm³                                       ∴ 1dm³ = 1 L

So,

                                      Volume  = 11.2 L

4 0
4 years ago
Read 2 more answers
Someone please help!!!!
Blababa [14]
I'm not 100% sure on this one, but I think it's C. 

Sorry, I'm not really good with Chemistry.


Hope this helps :)
8 0
3 years ago
Oxygen gas is collected at a pressure of 1.21 atm in a container which has a volume of 10.0 L. What temperature (in Kelvin) must
stiv31 [10]

Answer : The temperature of gas is, 295 K

Explanation :

To calculate the temperature of gas we are using ideal gas equation:

PV=nRT

where,

P = Pressure of gas = 1.21 atm

V = Volume of gas = 10.0 L

n = number of moles = 0.500 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of gas = ?

Now put all the given values in above equation, we get:

1.21atm\times 10.0L=0.500mole\times (0.0821L.atm/mol.K)\times T

T=294.8Kapprox 295K

Therefore, the temperature of gas is, 295 K

5 0
3 years ago
HELP ME I WILL MARK BRIANLIEST! ALOT OF POINTS. Question and answer r in photo.
Lemur [1.5K]

Answer:

the answer is b

Explanation:

5 0
3 years ago
Read 2 more answers
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