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Tanya [424]
4 years ago
11

If you wanted to buy an aquarium with only benthos in it which of the following would you buy

Chemistry
1 answer:
Tju [1.3M]4 years ago
6 0

Answer:

"Organisms in this tank are attached to the bottom, but use the sun to make food."

Explanation:

<em>"The principal food sources for the benthos are plankton and organic debris from land. In shallow water, larger algae are important, and, where light reaches the bottom, benthic photosynthesizing diatoms are also a significant food source."</em>

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What is the economic impact of too much calcium ions in a given source of water?
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Which subatomic particle plays the greatest part in determining the properties of an element?
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8 0
3 years ago
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ELEMENTS ARE CLASSIFIED AS METALS, NONMETALS, AND METALLOIDS. USE THE PERIODIC TABLE AND IDENTIFY TWO OF EACH CLASSIFICATION.
alekssr [168]

Answer:

Elements are classified into- metals – Nonmetals- Metalloids – Noble gases. State which of A, B, C, D is a:

1) Metallic element

2) Non-metallic element

3) Metalloid

4) Noble gas.

A) Is non-malleable, non-ductile and a poor conductor of electricity

B) Has lustre, is malleable and ductile and a good conductor of electricity

C) Is unreactive and inert and present in traces in air

D) Shows properties of both metals and nonmetals

Explanation:

3 0
3 years ago
Part a cyclohexane has a freezing point of 6.50 ∘c and a kf of 20.0 ∘c/m. What is the freezing point of a solution made by disso
Andrei [34K]

The mathematical expression for the depression in freezing point is given as:

\Delta T_{f}= k_{f}m

where, \Delta T_{f} = depression in freezing point

k_{f} = molal depression constant    (20.0 ^{o}Ckg/mole)

m = molality

Molality is defined as the ratio of number of moles of solute to the kg of the solvent

Number of moles  =\frac{given mass in g}{molar mass}

given mass  of biphenyl solute = 0.925 g

Molar mass of biphenyl  = 154.21 g/mol

Put the values,

number of moles of biphenyl =\frac{0.925 g}{154.21 g/mol}

= 0.0059 mole

Molality =\frac{number of moles of biphenyl solute}{mass of the solvent in kg}

Mass of cyclohexane solvent  = 25.0 g

Convert g into kg: 1 kg = 1000 g

Thus, mass of cyclohexane  = \frac{25.0}{1000}

= 0.025 kg

Now, put the values in the formula of molality:

Molality =\frac{0.0059 mole}{0.025 kg}

= 0.236 mole/kg or 0.236 m.

Calculate the depression in freezing point:

\Delta T_{f}= 20.0^{o}C kg/mole\times 0.236 mole/kg

= 4.72 ^{o}C

Now, \Delta T_{f} = T_{solvent} - T_{solution}

4.72 ^{o}C = 6.50^{o}C - T_{solution}

T_{solution} = 6.50^{o}C- 4.72 ^{o}C

= 1.78^{o}C

Hence, freezing point of the solution is 1.78^{o}C.



4 0
3 years ago
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