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astra-53 [7]
3 years ago
5

2 C2H6 + 7 026 H2O + 4 CO2

Chemistry
1 answer:
Kay [80]3 years ago
3 0

Answer:

Oxygen is limiting reactant

Explanation:

Based on the chemical reaction:

2C2H6 + 7O2 → 6H2O + 4CO2

<em>2 mole of ethane reacts with 7 moles of oxygen</em>

<em />

For a complete reaction of 5.25 moles of ethane are required:

5.25 moles Ethane * (7mol Oxygen / 2mol Ethane) = 18.38 moles of oxygen

As there are just 15.0 moles of oxygen

<h3>Oxygen is limiting reactant</h3>
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A heliox tank contains 32% helium and 68% oxygen. The total pressure in the tank is 475 kPa. What is the partial pressure of hel
Paladinen [302]

Answer:

152 kPa = Partial pressure O₂

Explanation:

Data by percent is the molar fraction . 100.

Molar fraction of Helium = 32/ 100 → 0.32

Molar fraction of O₂ = 68/100 → 0.68

Sum of molar fractions in a mixture = 1

0.68 + 0.32 = 1

If we apply the molar fraction, we can determine the partial pressure.

Mole fraction = Partial pressure / Total pressure

0.32 = Partial pressure O₂ / 475kPa →  0.32 . 475 kPa = Partial pressure O₂

152 kPa = Partial pressure O₂

8 0
3 years ago
Formula for Manganese Bromide Tetrahydrate
Lelu [443]

Answer:

I believe the molecular formula is MnBr2·4H2O or Br2H8MnO4

Explanation:

5 0
3 years ago
All atoms of an element have the same number of ________. electrons neutrons protons protons plus neutrons
Cloud [144]

Answer:

protons

Explanation:

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6 0
3 years ago
Answer pls
alukav5142 [94]

the answer is answer

7 0
3 years ago
Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. the initial temperature of the gas is 27.0c
Alla [95]

We have to know final temperature of the gas after it has done 2.40 X 10³ Joule of work.

The final temperature is: 75.11 °C.

The work done at constant pressure, W=nR(T₂-T₁)

n= number of moles of gases=6 (Given), R=Molar gas constant, T₂= Final temperature in Kelvin, T₁= Initial temperature in Kelvin =27°C or 300 K (Given).

W=2.4 × 10³ Joule (Given)

From the expression,

(T₂-T₁)=\frac{W}{nR}

(T₂-T₁)= \frac{2.40 X 10^{3} }{6 X 8.314}

(T₂-T₁)= 48.11

T₂=300+48.11=348.11 K= 75.11 °C

Final temperature is 75.11 °C.


6 0
3 years ago
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