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3 years ago

A car accelerates uniformly in a straight line from rest at the rate of 3.7 m/s2

Physics

1 answer:

lubasha [3.4K]3 years ago

3 0

Explanation:

Using equations of motion :

(A) we know that,

u = 0

a = 3.7 m/s^2

S = 63

${v}^{2} = {u}^{2} + 2as$

$v = \sqrt{0 + 2 \times 3.7 \times 63} = 21.6 \: m{s}^{ - 1}$

(B)

v = u + at

21.6 = 0 + 3.7 * t

t (time to reach 63 m) = 5.83 seconds

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3 years ago

Part 1: A rope has one end tied to a vertical support. You hold the other end so that the rope is horizontal. If you move the en

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Answer:

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4 years ago

A force of 10 N causes a spring to extend by 20 mm. Find a) the spring constant of the spring in N/m b) the extension of the spr

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(a) The spring constant is 500 N/m.

(b) The extension of the spring when 25 N force is applied is 0.05 m.

The given parameters:

Applied force, F = 10 N
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The spring constant is calculated as follows;

$F = kx\\\\k = \frac{F}{x} \\\\k = \frac{10}{20 \times 10^{-3}} \\\\k = 500 \ N/m$

The extension of the spring when 25 N force is applied is calculated as follows;

$F = kx\\\\x = \frac{F}{k} \\\\x = \frac{25}{500} \\\\x = 0.05 \ m$

The applied force to cause an extension of 5 mm is calculated as follows;

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Learn more about Hook's law here: brainly.com/question/12253978

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3 years ago

Argon makes up 0.93% by volume of air. Calculate its solubility (in mol/L) in water at 20°C and 1.0 atm. The Henry's law constan

vladimir2022 [97]

Answer:

S= 1.40x10⁻⁵mol/L

Explanation:

The Henry's Law is given by the next expression:

$S = k_{H} \cdot p$ (1)

where S: is the solubility or concentration of Ar in water, $k_{H}$ : is Henry's law constant and p: is the pressure of the Ar

Since the argon is 0.93%, we need to multiply the equation (1) by this percent:

$S = 1.5 \cdot 10^{-3} \frac{mol}{L\cdot atm} \cdot 1.0atm \cdot \frac{0.93}{100} = 1.40 \cdot 10^{-5} \frac{mol}{L}$

Therefore, the argon solubility in water is 1.40x10⁻⁵mol/L.

Have a nice day!

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3 years ago