Question

Subtract: 6/2x^+8x - x/4x^+12x-16 = 6/2x(x+4) - x/4(x+4)(x-1) = 6•2(x-1)/2x(x+4)•2(x-1) - x•x/4(x+4)(x-1)•x

Answer 1

Answer:

$\frac{-x^2+12x-12}{4x(x+4)(x-1)}$

Step-by-step explanation:

$\frac{6}{2x(x+4)}- \frac{x}{4(x+4)(x-1)}$

$\frac{6\cdot2(x-1)}{2x(x+4)\cdot2(x-1)}- \frac{x\cdot x}{4(x+4)(x-1)x}$

$\frac{12(x-1)}{4x(x+4)(x-1)}- \frac{x^2}{4x(x+4)(x-1)}$

$\frac{12(x-1)-x^2}{4x(x+4)(x-1)}$

$\frac{-x^2+12x-12}{4x(x+4)(x-1)}$