Answer:
We normally separate unreacted hydrogen from ammonia (product) in Haber process. The reaction mixture contains some ammonia, plus a lot of unreacted hydrogen and nitrogen. The mixture is cooled and compressed, causing the ammonia gas to condense into a liquid.
<span>There is only one formula to use and we should assume ideal gas. This equation is: PV=nRT. For the following questions manipulate this equation to get the answer.
1. n = PV/RT = (249*1000 Pa)(15.6 L)(1 m^3/1000 L)/(8.314 Pa-m^3/mol-K))(21+273) = 1.59 mol
2. P = nRT/V = (1.59)(8.314)(51+273)/(15.6/1000)(1000) = 274.55 kPa
3. Since the answer in #2 is more than 269 kPa, then the tires will likely burst.
4. Reduce pressure way below the limit 269 kPa.</span>
A) Answer D. Clouds forming high in the atmosphere are referred to as cirrus, cirrostratus, and cirrocumulus.
B) Clouds tend to form at higher altitudes because as<span> air rises, the moisture in it slowly reaches its saturation point and when this happens, tiny crystals of water start to condense and form clouds.
C) Precipitation: Water that falls to the ground from clouds, such as in rain, snow, sleet, or hail.</span>
Answer:
See attached picture.
Explanation:
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In this case, since butane has two common occurring structures, n-butane and isobutane, there is a way in which the tert-butyl radical can be formed upon the removal of a hydrogen from the isobutane form of butane as shown on the attached picture, wherein you can see that the radical is named by "tert" since the central carbon is bonded to three carbon atoms, that is why we classify it as tertiary. Moreover, it is a radical due to the presence of the bolded dot next to the tertiary carbon suggesting that it is very likely to bond with an other atom.
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If the forward reaction goes close to completion and has a high yield, that means the concentration of products will be higher than the concentration of reactants.
<span>So if the concentration of products is higher, Kc (equilibrium constant) will be greater than 1.
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Recall the calculation for the equilibrium constant for reaction. Picture below might help you.</span>