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Marrrta [24]
4 years ago
5

QUESTION 8

Chemistry
1 answer:
andrew-mc [135]4 years ago
6 0
I don't actually know this is a guess and this is false
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How many grams of Na2SO4 can be produced from 423.67 g of NaCl?
san4es73 [151]

Mass of  Na2SO4= 514.18 grams

<h3>Further explanation</h3>

Given

423.67 g of NaCl

Required

mass of  Na2SO4

Solution

Reaction

2NaCl + H2SO4 → Na2SO4 + 2HCl

mol NaCl :

= 423.67 g : 58.5 g/mol

= 7.24

From the equation, mol Na2SO4 :

= 1/2 x mol NaCl

= 1/2 x 7.24

= 3.62

Mass  Na2SO4 :

= 3.62 mol x 142,04 g/mol

= 514.18 grams

4 0
3 years ago
What is wrong with the structures that you obtain using the incorrect arrows?
Liono4ka [1.6K]
-A bromine with an incomplete octet and a positive charge.
-A bromine with an incomplete octet and a positive charge and an oxygen with ten valence electrons and two charges.
-A compound with the bond between a bromine and an oxygen with three bonds.
7 0
4 years ago
Please help on this one?
Bezzdna [24]

Answer:

\text{C. } _{36}^{85}\text{Kr}

Explanation:

Your nuclear equation is  

_{35}^{85}\text{Br} \longrightarrow \, _{-1}^{0}\text{e} +\, _{x}^{y}\text{X}

The main point to remember in balancing nuclear equations is that

  • the sum of the superscripts and must be the same on each side of the equation.
  • the sum of the subscripts must be the same on each side of the equation.  

Then  

85 = 0 + y, so y = 85 - 0 = 0  

35 = -1 + x, so x = 35 + 1 = 36

The nucleus with atomic number 36 and atomic mass 85 is krypton-85.  

The nuclear equation becomes  

_{35}^{85}\text{Br} \longrightarrow \, _{-1}^{0}\text{e} + \, _{36}^{85}\text{Kr}

4 0
3 years ago
Read 2 more answers
What is the activity series of metals?
steposvetlana [31]

Answer:

C.A list of metals arranged in order of reactivity

7 0
3 years ago
Read 2 more answers
A. draw the structure of the tetrahedral intermediate initially formed in the reaction shown. you do not have to consider stereo
julsineya [31]
The reaction is shown below, Acid protonates the carbonyl oxygen and makes the carbonyl carbon more electrophilic. Water attacks on activated carbonyl group and forms a tetrahedral intermediate.

Intermediate:
                    Structure of Intermediate is shown both in 2-D and 3-D (below attached). 

Carbonyl group is regenerated with the elimination of ethanol.

Reaction is as below, The final product is carboxylic acid.

4 0
3 years ago
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