Which would have a longer vector arrow?

When jogging outside you accidently bump into a curb. Your feet stop but your body continues to move forward and you end up on t

gayaneshka [121]

Newtons first law of motion
object in motion stays in motion, object at rest stays at rest unless acted upon an unbalanced force

5 0

3 years ago

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Describe the path of an electrical impulse as it moves through a neuron. You must use the words axon

Nat2105 [25]

Answer:

The nerve impulse is not transmitted with the same speed in all neurons. It depends on whether or not the axon is surrounded by cells, the Schwann cells, which produces a white substance, the myelin sheath, which prevents the passage of the nerve impulse and causes you to "jump" between the spaces without the sheath of Myelin (Ranvier nodules), so the speed will be higher.

This type of nerve impulse spread is called "saltatory conduction or spread."

Explanation:

Neurons are cells that have the ability to transmit the nerve impulse in the form of an electric current. The nerve impulse only spreads in one direction. When a neuron is stimulated, electrical changes originate that begin in the dendrites, pass through the neuronal body, and end in the axon.

Neurons can also be classified according to whether or not they have myelin:

- Myelinic neurons Its axons are thicker and the nerve impulse spreads more quickly thanks to the saltatory conduction.

- Unmyelinated neurons They grow myelin, so they drive the nerve impulse more slowly.

The nerve impulse is transmitted along a neuron through a depolarization process:

- Initially, the membrane is polarized. On the outside of the membrane, ions with positive charge abound and on the inside, those with negative charge. This is maintained by the action of the sodium-potassium pump and is called the resting potential.

- When a stimulus arrives, the permeability increases for the sodium ions, which enter the cell, so that the polarity is reversed at that point, leaving more positive charge inside in that area. This alteration is called action potential.

- This depolarization leads to the redistribution of the ions, the nearby sodium channels open, and the adjacent area is also depolarized, and this, in turn, to that of the area that follows, as if they were the dominoes . In this way the nerve impulse travels like a wave along the axon.

- Once the nerve impulse has traveled the entire axon, in thousandths of a second, repolarization or restoration of the ion concentrations characteristic of the resting state occurs.

3 0

3 years ago

Two 10-cm-diameter metal plates 1.0 cm apart are charged to {12.5 nC. They are suddenly connected together by a 0.224-mm- diamet

Alekssandra [29.7K]

Answer:

(a).The maximum current in the wire is $4.217\times10^{5}\ A$ .

(b). The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c).The current also decrease with time.

(d). The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

Explanation:

Given that,

Diameter of metal plates = 10 cm

Distance between the plates = 1.0 cm

Charged = 12.5 nC

Diameter of copper wire = 0.224 mm

We need to calculate the cross section area of the plates

Using formula of area

$A=\pi r^2$

Put the value into the formula

$A=\pi\times(5\times10^{-2})^2$

$A=7.85\times10^{-3}\ m^2$

We need to calculate the capacitor

Using formula of capacitor

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times7.85\times10^{-3}}{1.0\times10^{-2}}$

$C=6.94\times10^{-12}\ F$

We need to calculate the resistance of the wire

Using formula of resistivity

$R=\dfrac{\rho l}{A}$

Put the value into the formula

$R=\dfrac{1.7\times10^{-8}\times1.0\times10^{-2}}{\pi\times(0.1125\times10^{-3})^2}$

$R=4.27\times10^{-3}\ \Omega$

We need to calculate the voltage

Using formula of charge

$q=CV$

$V=\dfrac{q}{C}$

Put the value into the formula

$V=\dfrac{12.5\times10^{-9}}{6.94\times10^{-12}}$

$V=1.801\times10^{3}\ V$

(a). We need to calculate the current

Using formula of current

$I=\dfrac{V}{R}$

$I=\dfrac{1.801\times10^{3}}{4.27\times10^{-3}}$

$I=421779.85\ A$

$I=4.217\times10^{5}\ A$

(b). We need to calculate the electric field

Using formula of electric field

$E=\dfrac{kq}{r^2}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times12.5\times10^{-9}}{(1.0\times10^{-2})^2}$

$E=11.2\times10^{5}\ N/C$

The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c). In this case, the voltage between the capacitor plates decreases as the charge decreases with time.

The current is directly proportional to the voltage between the plates .

Hence, The current also decrease with time.

(d). We need to calculate the total amount of energy dissipated in the wire

Using formula of energy

$E=\dfrac{1}{2}CV^2$

Put the value into the formula

$E=\dfrac{1}{2}\times6.94\times10^{-12}\times(1.801\times10^{3})^2$

$E=1.126\times10^{-5}\ J$

The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

Hence, (a).The maximum current in the wire is $4.217\times10^{5}\ A$ .

(b). The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c).The current also decrease with time.

(d). The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

8 0

3 years ago

Please need help on this

Vera_Pavlovna [14]

Answer:

i have no idea

Explanation:

it could be B. but i dont belive in myself sooooooooooo.....ehhhh yeah

4 0

3 years ago

_____ is when a sound wave bounces off a surface back into the medium from which it came.

denpristay [2]

Correct answer is, Reflection

8 0

3 years ago

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