Answer: 9.33fm
Explanation:
Similarly as with a cut diffraction happens when part of the proliferating wave is cut off. This will occur for any object of request with a similar size as the wavelength of the diffracting wave.
Note, the object is moving at 14% of the speed of light. Be that as it may, the gamma factor is just 1% so taking care of the issue either relativistic or non relativistic conditions offers comparative responses.
Note: The size of the object has to be of the order of the wavelength of 10MeV. Therefore, size apperture that would be necessary to observe diffraction effect would be 9.33fm.
The calculations are in the attachment below:
Kinetic energy is an expression of the fact that a moving object can do work on anything it hits; it quantifies the amount of work the object could do as a result of its motion. And potential energy <span>is the </span>energy<span> that is stored in an object due to its position relative to some zero position. </span><span> We calculate as follows:
KE + PE = mv^2 / 2 + mgh
Total energy = .4(25)^2/2 + .4(9.81)(1.2)
Total energy = 129.71 J = 130 J <------- OPTION A</span>
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<h3> Collector Current at Saturation :</h3>
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<h3> Value Of Cut - off Voltage : </h3>
Therefore ,
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<h3>Collector Current ,</h3>
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<h3> Collector to emitter Voltage : </h3>
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<h3>Q - point are :</h3>
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<h3>Q - point located on the DC load line as shown in fig ~</h3><h3 /><h3 /><h3 /><h3 />
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Hope Helps!:)
