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3 years ago

I would like a list of random, interesting facts about Francium.

1 answer:

6 0

It has the highest equivalent weight of all elements.
Prior to its discovery, it was simply referred to as eka-caesium.
The most stable isotope, Fr-223, has the longest half-life at 21.8 minutes.
Francium has thirty-four known isotopes, with only two of them occurring in nature.
It is the most unstable of all elements that occur naturally.
Hope this helps.

You might be interested in

Which of the following statements is FALSE?

Alborosie

Answer:

The answer to your question is: letter E

Explanation:

A. This option is correct, the n = 3 shell only has subshells: s, p and d, and shell n = 4 or 5 have f subshell.

B. This option is true in subshell p could be at most 6 electrons and 3 suborbitals.

C. This option is correct orbital "s" is a sphere.

D. This option is correct, in subshell d could be at most 10 electrons and 5 orbitals.

E. This option is false, hydrogen only has 1 electron and then one subshell (s).

6 0

3 years ago

Stronger acids are those that —

Harlamova29_29 [7]

F. hold on to their protons more strongly

7 0

3 years ago

Why is light helpful? You can just give one reason

hoa [83]

Light is helpful because it allows us to see things around us.
I hope this helps :)

3 0

2 years ago

Answer the following for the reaction: 3AgNO3(aq)+Na3PO4(aq)→Ag3PO4(s)+3NaNO3(aq)

Brums [2.3K]

Answer:1) Volume of $AgNO_3$ required is 55.98 mL.

2) 0.62577 grams of $Ag_3PO_4$ is produced.

Explanation:

$3AgNO_3(aq)+Na_3PO_4(aq)\rightarrow Ag_3PO_4(s)+3NaNO_3(aq)$

1) Molarity of $AgNO_3,M_1=0.225 M$

Volume of $AgNO_3.V_1=?$

Molarity of $Na_3PO_4,M_2=0.135 M$

Volume of $Na_3PO_4,V_2=31.1 mL=0.0311 L$

$Molarity=\frac{\text{number of moles}}{\text{volume of solution in liters}}$

$\text{number of moles }Na_3PO_4=M_2\times V_2=0.135 mol/L\times 0.0311 L=0.0041985 moles$

According to reaction, 1 mole of $Na_3PO_4$ reacts with 3 mole of $AgNO_3$ , then, 0.0041985 moles of $Na_3PO_4$ will react with:

$\frac{3}{1}\times 0.0041985$ moles of $AgNO_3$ that is 0.0125955 moles.

$M_1=0.225 M=\frac{\text{number of moles of }AgNO_3}{V_1}$

$V_1=\frac{0.0125955 moles}{0.225 M}=0.05598 L=55.98 mL$

Volume of $AgNO_3$ required is 55.98 mL.

$Molarity=0.195 M=\frac{\text{number of moles}}{\text{volume of solution in liters}}$

Number of moles of $AgNO_3=0.195\times 0.023 L=0.004485 moles$

According to reaction, 3 moles of $AgNO_3$ gives 1 mole of $Ag_3PO_4$ , then 0.004485 moles of $AgNO_3$ will give: $\frac{1}{3}\times 0.004485$ moles of $Ag_3PO_4$ that is 0.001495 moles.

Mass of $Ag_3PO_4$ =

Moles of $Ag_3PO_4$ × Molar Mass of $Ag_3PO_4$

= 0.001495 moles × 418.58 g/mol = 0.62577 g

0.62577 grams of $Ag_3PO_4$ is produced.

7 0

3 years ago

40 POINTS PUT A GOOD ANSWER

Andreyy89

Answer:

B What role do animals have in the carbon cycle?

Group of answer choices

use water and release oxygen

use sugar and release carbon

use carbon and release oxygen

use carbon and release nitrogen

D, E Select TWO statements that describe what the scientists will observe in the ecosystem after fossil fuels have been extracted and burned.

Group of answer choices

There is more available space for carbon to become fossil fuels.

There is less carbon in storage.

There will be less carbon in the water.

There is more carbon in the atmosphere.

There will be more carbon respired by organisms.

There will be less carbon released through decomposition.

Explanation:

Animals obtain energy through sugar from the food they eat and release carbon into the air through respiration. Therefore, they partake in the carbon cycle by using sugar and releasing energy.

As far as the second question, when fossil fuels are burned, the carbon contained within them is released into the atmosphere in the form of carbon dioxide. So, there will obviously be a greater amount in the atmosphere.

I would like to apologise in advance if either of my option choices were incorrect.

6 0

2 years ago