determine the percent of composition
Answer:
The molecular formula of the compound = 
The empirical formula of the compound = 
The balanced chemical equation for this reaction:

Explanation:
Compound that is 27.87% P and 72.13% S by mass and has a molar mass of 444.56 g/mol.
Molar mass of compound = 444.56 g/mol
Number of phosphorus atom = x
Number of sulfur atom = y
Atomic mass of phosphorus 31 g/mol
Atomic mass of sulfur = 32 g/mol
Percentage of element in compound :

Phosphorus :

x = 4
Sulfur :

y = 10
The molecular formula of the compound = 
Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.
The empirical formula of the compound = 
The balanced chemical equation for this reaction:

Answer:
The ratio 35Cl/37Cl = 3/1
Explanation:
<u>Step 1:</u> Data given
Chlorine has 2 isotopes:
- mass = 35 g/mol
- mass = 37 g/mol
Average molar mass of chlorine = 35.5 grams
<u>Step 2: </u>Calculate the % of isotopes
35x + 37y = 35.5
x+y = 1 or x = 1-y
35(1-y) + 37y = 35.5
35-35y +37y = 35.5
0.5 = 2y
y = 0.25 = 37Cl
x = 1 - 0.25 = 0.75 = 35Cl
<u>Step 3: </u>
The ratio 35Cl/37Cl = 0.75/0.25 = 3/1
Each molecule of Sr₃(PO₄)₂ contains 3 moles of Sr
So 3 moles of Sr⁺² ions are in one mole of Sr₃(PO₄)₂.