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Allushta [10]
2 years ago
5

An exothermic reaction is a chemical reaction where heat is

Chemistry
2 answers:
ch4aika [34]2 years ago
3 0
Emitted/given off. exo is a way to remember that is is going away. think of a flame. the heat is emitted off onto you.
Aleks04 [339]2 years ago
3 0
Emitted/give enough is the correct answer
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Please help me with this question !!!
Art [367]

Density of the vinegar is higher than the density of the oil.

Explanation:

Density of the vinegar is higher than the density of the oil. The consequence of this is that the oil will be the top layer in the pitcher while the vinegar is at the bottom layer in the pitcher.

When mixing oil and vinegar will not produce a mixture because the oil contains non-polar molecules while vinegar is a solution of acetic acid in water and both of them are polar molecules.

Learn more about:

liquids with different densities

brainly.com/question/9490207

#learnwithBrainly

4 0
3 years ago
The melting point of unknown substance A is 15°C and its boiling point is 95°C. Sketch a
Igoryamba

Answer:

Idk if this is right but i hope it helps... sorry if it's wrong

Explanation:

4 0
3 years ago
4. Which is produced when a base reacts with water?
Dennis_Churaev [7]

Answer:

hydroxide ion

Explanation:

I took the quiz

5 0
3 years ago
Read 2 more answers
based on the cause and effect relationship between the magnets, which phenomenon is the teacher modeling for her students.
faltersainse [42]

Answer:

Someone breaking up.

Explanation:

8 0
2 years ago
Se tiene una solución acuosa 2M de carbonato de potasio. Expresar su concentración en %p/v y Normalidad.
zepelin [54]

Answer:

Normalidad = 4N

%p/V = 27.6%

Explanation:

La solución 2M de carbonato de potasio contiene 2moles de carbonato por litro de solución. La normalidad son los equivalente de carbonato de potasio (2eq/mol) por litro de solución:

2moles * (2eq/mol) = 4eq / 1L = 4N

El porcentaje peso volumen es el peso de carbonato en gramos dividido en el volumen en mL por 100:

%p/V:

Masa K2CO3 -Masa molar: 138.205g/mol-

2moles * (138.205g/mol) = 276g K2CO3

Volumen:

1L * (1000mL/1L) = 1000mL

%p/V:

276g K2CO3 / 1000mL * 100

<h3>%p/V = 27.6%</h3>
6 0
2 years ago
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