Why does Magnesium and Copper can't react with Sodium hydroxide ?

What is the voltage of a battery that powers a light with .43 A and has a resistance of 3.5 ohms? A) 1.505 V Eliminate B) 3.07 V

Mrac [35]

To determine the voltage of the battery above, we use Ohm's Law which relates voltage (V), current (I) and resistance (R) in a circuit. It is expressed as V = IR. We calculate as follows:

V = IR
V = .43 A ( 3.5 ohms )
V = 1.505 V

Therefore, the correct answer is option A.

5 0

3 years ago

Which substance is NOT a compound?

enyata [817]

B, sodium because if you look at your periodic table it is the only element not compounded with another

8 0

3 years ago

Read 2 more answers

A truck tire has a volume of 218 L and is filled with air to 35.0 psi at 295 K. After a drive, the air heats up to 318 K. (b) If

Alenkasestr [34]

The pressure (in psi) is 37.1

We are given the following information:

- The initial temperature of the air, $T_{1}=295 \mathrm{~K}$

- The initial pressure, $P_{1}=35.0 \mathrm{psi}$ .

- The initial volume, $V_{1}=208 \mathrm{~L}$

- The final temperature, $T_{2}=319 \mathrm{~K}$

- The increase in the volume is $2 \%$ , that is, $\Delta V=\frac{2}{100} V_{1}$ where $\Delta V$ is the increase in the volume.

The combined gas law states that a fixed amount of an ideal gas obeys the following equation: $\frac{P V}{T}=$ constant, where:

- P is the Pressure of the gas.

- V is the Volume of the gas.

- n is the number of moles of gas.

$R=8.31 \mathrm{~J} / \mathrm{mol} \mathrm{K}=0.0821 \mathrm{~L} \cdot {atm} / \mathrm{mol} \cdot \mathrm{K}$ is the Universal Gas constant.

- T is the absolute temperature of the gas.

The final volume of the air is:

$\begin{aligned}V_{2} &=V_{1}+\Delta V \\&=V_{1}+\frac{2}{100} V_{1} \\&=\frac{102}{100} V_{1}\end{aligned}$

Equating the initial and final state, we have:

$\begin{aligned}\frac{P_{2} V_{2}}{T_{2}} &=\frac{P_{1} V_{1}}{T_{1}} \\\Rightarrow P_{2} &=\frac{V_{1}}{V_{2}} \times \frac{T_{2}}{T_{1}} \times P_{1} \\&=\frac{V_{1}}{102 V_{1} / 100} \times \frac{319 \mathrm{~K}}{295 \mathrm{~K}} \times 35.0 \mathrm{psi} \\& \approx 37.1 \mathrm{psi}\end{aligned}$

The ideal gas law states that a universal constant for an ideal gas is the ratio of the product of pressure and temperature to the product of the number of moles and absolute temperature. The resultant equation is known as the combined gas law if the number of moles in the ideal gas law is set to a constant.

Learn more about combined gas law brainly.com/question/13154969

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8 0

2 years ago

In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for

inessss [21]

Answer:

The standard cell potential of the reaction is 0.78 Volts.

Explanation:

$Cu^{2+}(aq)+Fe(s)\rightarrow Cu(s)+Fe^{2+}(aq)$

Reduction at cathode :

$Cu^+(aq)+2e^-\rightarrow Cu(s)$

Reduction potential of $Cu^{2+}$ to Cu= $E^o_{1}=0.34 V$

Oxidation at anode:

$Fe(s)\rightarrow Fe^{2+}(aq)+2e^-$

Reduction potential of $Fe^{2+}$ to Fe= $E^o_{2}=-0.44 V$

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}$

Putting values in above equation, we get:

$E^o_{cell}=0.34V -(-0.44 V)=0.78 V$

The standard cell potential of the reaction is 0.78 Volts.

3 0

3 years ago

How many grams of lithium are in a 1320 [mAh] cell phone battery? Note that [mAh] is a unit of charge.

AURORKA [14]

Answer:

0.396 grams of lithium

Explanation:

Lithium-ion batteries have the main feature of using lithium salts as a "bridge" between the positive pole (anode) to the negative (cathode) to allow the passage of energy that will give life to our device. In the case of lithium polymer batteries, the difference is that the lithium salt is contained in a polymer, or gel, to keep it safe from spills.

In both cases, when the battery is discharging, lithium ions travel from the cathode to the anode through their "bridges" to supply the energy until all the ions are in the anode, it is at this time when the battery is out of stock The ions travel in the opposite direction during charging (from the anode to the cathode).

<u>The calculation used to determine the amount of lithium that the lithium cell batteries have is as follows</u>:

0.3 x amp hour capacity = g of lithium

where amp hour = Ah

<u>In our case</u>:

0.3 x 1.32 = 0.396 g of lithium

5 0

3 years ago