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mario62 [17]
2 years ago
14

A compound consists of 0.154 g sodium, 0.238 g chlorine, and 0.322 g oxygen

Chemistry
1 answer:
Alika [10]2 years ago
4 0

Answer:

                        Empirical Formula = NaClO₃

Explanation:

                     As the question is incomplete so we will assume that the question is asking for finding out the empirical formula of the compound made up of these elements,

Step 1: <u>Calculate Moles of each element as:</u>

Moles (Na)  =  0.154 g / 22.99 g/mol  =  0.006698

Moles (Cl)  =  0.238 g / 35.45 g/mol  =  0.006713

Moles (O)  =  0.322 g / 16.00 g/mol  =  0.02012

Step 2: <u>Calculate mole ratio and simplify it,</u>

Na                                    <u>Cl  </u>                                     O

0.006698                       <u>0.006713</u>                      0.02012 

0.006698/0.006698     <u>0.006713/0.006698</u> 0.02012/0.006698

              1.00                       <u> 1.00</u>                                     3.00

Result:

           Empirical Formula = NaClO₃

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3 years ago
The unit cell for cr2o3 has hexagonal symmetry with lattice parameters a = 0.4961 nm and c = 1.360 nm. If the density of this ma
IRINA_888 [86]

To calculate the packing factor, first calculate the area and volume of unit cell.

Area is calculated as:

A=6R^{2}\sqrt{3}

Here, R is radius and is related to a as follows:

R=\frac{a}{2}

Putting the value in expression for area,

A=6(\frac{a}{2})^{2}\sqrt{3}=1.5a^{2}\sqrt{3}

The value of a is 0.4961 nm

Since, 1 nm=10^{-7}cm

Thus, 0.4961 nm=4.961\times 10^{-8} cm

Putting the value,

Area=1.5(4.961\times 10^{-8}cm)^{2}\sqrt{3}=6.39\times 10^{-15}cm^{2}

Now, volume can be calculated as follows:

V=Area\times c

The value of c is 1.360 nm or 1.360\times 10^{-7} cm

Putting the value,

V=(6.39\times 10^{-15}cm^{2})\times (1.360\times 10^{-7} cm)=8.7\times 10^{-22}cm^{3}

now, number of atom in unit cell can be calculated by using the following formula:

n=\frac{\rho N_{A}V_{c}}{A}

Here, A is atomic mass of Cr_{2}O_{3} is 151.99 g/mol.

Putting all the values,

n=\frac{(5.22 g/cm^{3})(6.023\times 10^{23} mol^{-1})(8.7\times 10^{-22}cm^{3})}{(151.99 g/mol)}\approx 18

Thus, there will be 18 Cr_{2}O_{3} units in 1 unit cell.

Since, there are 2 Cr atoms and 3 oxygen atoms thus, units of chromium and oxygen will be 2×18=36 and 3×18=54 respectively.

The atomic radii of Cr^{3+} and O^{2-} is 62 pm and 140 pm respectively.

Converting them into cm:

1 pm=10^{-10}cm

Thus,

r_{Cr^{3+}}=6.2\times 10^{-9}cm

and,

r_{O^{2-}}=1.4\times 10^{-8}cm

Volume of sphere will be sum of volume of total number of cations and anions thus,

V_{S}=V_{Cr^{3+}}+V_{O^{2-}}

Since, volume of sphere is V=\frac{4}{3}\pi r^{3},

V_{S}=36\left ( \frac{4}{3}\pi (r_{Cr^{3+})^{3}} \right )+54\left ( \frac{4}{3}\pi (r_{O^{2-})^{3}} \right )

Putting the values,

V_{S}=36\left ( \frac{4}{3}(3.14) (6.2\times 10^{-9} cm)^{3}} \right )+54\left ( \frac{4}{3}(3.14) (1.4\times 10^{-8} cm)^{3}} \right )=6.6\times 10^{-22}\times 10^{-8}cm^{3}

The atomic packing factor is ratio of volume of sphere and volume of crystal, thus,

packing factor=\frac{V_{S}}{V_{C}}=\frac{6.6\times 10^{-22}cm^{3}}{8.7\times 10^{-22}cm^{3}}=0.758

Thus, atomic packing factor is 0.758.

6 0
3 years ago
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Answer:

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Explanation:

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density = 29 g/cm³

We have

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We have the final answer as

<h3>5.24 mL</h3>

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zvonat [6]

In 1 molecule of the compound C₆H₁₂O₂ there are 12 moles of hydrogen atoms

<h3>Further explanation</h3>

Given

C₆H₁₂O₂ compound

Required

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Solution

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2 years ago
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