Question

A compound consists of 0.154 g sodium, 0.238 g chlorine, and 0.322 g oxygen

Answer 1

Answer:

                        Empirical Formula = NaClO₃

Explanation:

                     As the question is incomplete so we will assume that the question is asking for finding out the empirical formula of the compound made up of these elements,

Step 1: Calculate Moles of each element as:

Moles (Na)  =  0.154 g / 22.99 g/mol  =  0.006698

Moles (Cl)  =  0.238 g / 35.45 g/mol  =  0.006713

Moles (O)  =  0.322 g / 16.00 g/mol  =  0.02012

Step 2: Calculate mole ratio and simplify it,

Na                                    Cl                                       O

0.006698                       0.006713                      0.02012 

0.006698/0.006698     0.006713/0.006698 0.02012/0.006698

              1.00                        1.00                                     3.00

Result:

           Empirical Formula = NaClO₃