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solong [7]
4 years ago
9

Please need help on this

Physics
1 answer:
emmainna [20.7K]4 years ago
5 0
I think the first one may be bicycle. Not sure about the others though, sorry.
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HELP HELP HELP HELP HELPPPPPPPPPPP
Firdavs [7]

Initial velocity (u) = 2 m/s

Acceleration (a) = 10 m/s^2

Time taken (t) = 4 s

Let the final velocity be v.

By using the equation,

v = u + at, we get

or, v = 2 + 10 × 4

or, v = 2 + 40

or, v = 42

The final velocity is 42 m/s.

5 0
3 years ago
Read 2 more answers
It is reasonable to conclude that the God of the Bible created all matter and started the motions now observed in the universe b
KIM [24]

Answer:

A

because it's the creation of the Lord

4 0
3 years ago
Read 2 more answers
A gas at 5.00 atm pressure was stored in a tank during the winter at 5.0 °C. During the summer, the temperature in the storage a
saw5 [17]

Answer:

a) 5.63 atm

Explanation:

We can use combined gas law

<em>The combined gas law</em> combines the three gas laws:

  • Boyle's Law,   (P₁V₁ =P₂V₂)
  • Charles' Law  (V₁/T₁ =V₂/T₂)
  • Gay-Lussac's Law.  (P₁/T₁ =P₂/T₂)

It states that the ratio of the product of pressure and volume and the absolute temperature of a gas is equal to a constant.

P₁V₁/T₁ =P₂V₂/T₂

where P = Pressure, T = Absolute temperature, V = Volume occupied

The volume of the system remains constant,

So, P₁/T₁ =P₂/T₂

a) \frac{5}{278} =\frac{P_2}{313}  \\\\P_2=\frac{5*313}{278}\\ P_2 = 5.63 atm

7 0
4 years ago
1:a boy 2 a girl pulling a heavy crate at the same time w/10 unite of force each.What is the net force acting on the object
vovangra [49]
The maximum magnitude of the net force on the box is 20 N, which is only possible if the boy and the girl pull the box together in the same direction, horizontally and parallel to the ground.
The minimum magnitude of the net force on the box is 0 N, which will occur when the boy and the girl pull the box together in the parallel but opposite direction.
If either of them pulls at an angle from the horizontal, then the magnitude of the net force will be between 0 N and 20 N.
8 0
3 years ago
A particle is moving along a circular path of 2-m radius such that its position as a function of time is given by u = (5t 2) rad
OverLord2011 [107]

Answer:

Explanation:

Given

radius of  path r=2\ m

Velocity of Particle \theta =5t^2 rad

where t=time in seconds

angular velocity of particle is given by

\omega =\frac{\mathrm{d} \theta }{\mathrm{d} t}

\omega =2\times 5t=10\cdot t

And angular acceleration is given by

\alpha =\frac{\mathrm{d} \omega }{\mathrm{d} t}

\alpha =10 rad/s^2

tangential acceleration is a_t=\alpha \times r

a_t=10\times 2=20\ m/s^2

Centripetal acceleration a_c=\omega ^2\times r

a_c=(10t)^2\times 2=200t^2

net acceleration is sum of tangential and centripetal force at any time t is given by

a_{net}=\sqrt{(a_c)^2+(a_t)^2}

a_{net}=\sqrt{(200t)^2+(20)^2}

a_{net}=20\sqrt{(10t)^2+1}\ m/s

                 

8 0
3 years ago
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