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Lubov Fominskaja [6]
3 years ago
5

What is the law of reflection?

Physics
2 answers:
Anuta_ua [19.1K]3 years ago
8 0
The law of reflection are, as follows:

The incident Ray, the reflected Ray and the normal to the reflection surface at the point of the incidence lie in the same plane.

If this does not make since than I hope you know I tried.
tia_tia [17]3 years ago
4 0
You can observe this law in practice if <span>a ray of light reflects off of a flat mirror. 
</span>
Law of reflection states that both direction of both incoming and outgoing rays of light make the same angle with respect to surface normal.
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A 20 kg mass is moving at 10 m/s and collides with a stationary 5 kg mass, transferring all its momentum in the collision, what
Fudgin [204]

Answer:

v = 40 [m/s].

Explanation:

Linear momentum is defined as the product of mass by Velocity. In this way, by means of the following equation, we can calculate the momentum.

P=m*v\\

where:

m = mass [kg]

v = velocity [m/s]

P =20*10\\P =200 [kg*m/s]

Since all momentum is transferred, we can say that this momentum is equal for the mass of 5 [kg]. In this way, we can determine the speed after the impact.

v = P/m\\v = 200/5\\v = 40 [m/s]

3 0
3 years ago
When Earth runs into the dust trail left behind by a comet that is orbiting the Sun, Earth experiences a _____.
tekilochka [14]
The answer to this question is: C) Meteor Shower
7 0
3 years ago
Read 2 more answers
I need help with #40 need answer and show me what you multiplied please
ale4655 [162]
(0.5)×(0squared)×(3)=(1.5j)
3 0
3 years ago
An electron passes location &lt; 0.02, 0.04, -0.06 &gt; m and 5 us later is detected at location &lt; 0.02, 1.62,-0.79 &gt; m (1
hram777 [196]

Answer:

(a)

Average velocity = < 0, 316000, 146000> m/s

(b) < 0, 2.844, 1.314 > m

Explanation:

r1 = < 0.02, 0.04, - 0.06 > m

r2 = < 0.02, 1.62, - 0.79 > m

time, t = 5 micro second = 5 x 10^-6 s

(a) Average velocity is defined as the ratio of total displacement to the total time taken.

Displacement = r = r2 - r1

r = < 0.02 - 0.02, 1.62 - 0.04, - 0.79 + 0.06 > m

r = < 0, 1.58, - 0.73 > m

So. Average velocity =  \frac{< 0, 1.58, - 0.73 >}{5 \times 10^{-6}}

Average velocity = < 0, 316000, 146000> m/s

Average velocity = < 0, 316000, 146000> m/s

(b)

Distance = velocity x time

Here time, t = 9 micro second

d =  < 0, 316000, 146000>  x 9 x 10^-6 m

d = < 0, 2.844, 1.314 > m

5 0
3 years ago
A 97 kg man lying on a surface of negligible friction shoves a 62 g stone away from himself, giving it a speed of 2.6 m/s. What
tangare [24]

Answer:

man will move in opposite direction with speed

v_1 = 1.66 \times 10^{-3} m/s

Explanation:

As we know that man is lying on the friction-less surface

so here net force along the surface is zero

so if we take man + stone as a system then net change in momentum of this system will become zero

so here we have

P_i = P_f

0 = m_1v_1 + m_2v_2

here we have

0 = (97)v_1 + 0.062(2.6)

v_1 = -\frac{0.1612}{97}

v_1 = -1.66 \times 10^{-3} m/s

3 0
3 years ago
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