Answer:
it has three atoms of hydrogen on each side.
Explanation:
it must be equal on both sides and answer D. is the most specific
Answer:
a) f=0.1 Hz ; b) T=10s
c)λ= 36m
d)v=3.6m/s
e)amplitude, cannot be determined
Explanation:
Complete question is:
Determine, if possible, the wave's (a) frequency, (b) period, (c) wavelength, (d) speed, and (e) amplitude.
Given:
number of wave crests 'n'= 5
pass in a time't' 54.0s
distance between two successive crests 'd'= 36m
a) Frequency of the waves 'f' can be determined by dividing number of wave crests with time, so we have
f=n/t
f= 5/ 54 => 0.1Hz
b)The time period of wave 'T' is the reciprocal of the frequency
therefore,
T=1/f
T=1/0.1
T=10 sec.
c)wavelength'λ' is the distance between two successive crests i.e 36m
Therefore, λ= 36m
d) speed of the wave 'v' can be determined by the product of frequency and wavelength
v= fλ => 0.1 x 36
v=3.6m/s
e) For amplitude, no data is given in this question. So, it cannot be determined.
Answer:
Explanation:
The mass of the deuteron = mass of the proton + mass of the neutron + mass equivalent of the energy of 2.2 Mev evolved.
I amu = 931 Mev
2.2 Mev = 2.2 / 931 amu
= ( 2.2 / 931 )x 1.6726 x 10⁻²⁷
= .00395 x 10⁻²⁷
The mass of the deuteron =( 1.6726 + 1.6749 + .00395)x 10⁻²⁷ kg
= 3.35145 x 10⁻²⁷ kg
b ) Momentum of gamma ray
= h / λ ( h is plank's constant and λ is wavelength of gamma ray )
= hυ / υλ ( υ is frequency of gamma ray )
= E / c ( E is energy of photon and c is velocity o light )
= 2.2 x 10⁶ x 1.6 x 10⁻¹⁹ J / 3 x 10⁸
= 1.173 x 10⁻²¹ Kg m /s
This will be the momentum of deuteron also
Kinetic energy
= p² / 2m ( p is momentum and m is mass of deuteron )
= ( 1.173 x 10⁻²¹ )² / ( 2 x 3.35145 x 10⁻²⁷)
= 1.376 x ⁻¹⁵ J
Energy of gamma ray
= 2.2 x 10⁶ x 1.6 x 10⁻¹⁹ J
= 3.52 x 10⁻¹³ J
So kinetic energy of deuteron is smaller than energy of gamma ray photon .
Explanation:
Using kinematics,
t = 10s
v = 0m/s
a = -9.8m/s^2
Therefore u = v - at = 0 - (-9.8)(10) = 98m/s.
See the attached figure.
The black arrows represent the two given vectors. The dashed black arrows are these same vectors, but translated so that the end of one vector is aligned with the start of another.
The red vector is their sum.
In case you also need to find the magnitude and direction of the sum, we have
A = (120 N) (cos(30°) i + sin(30°) j) = (60√3 i + 60 j) N
B = (-100 N) (cos(90°) i + sin(90°) j) = (-100 j) N
⇒ A + B = (60√3 i - 40 j) N
⇒ ||A + B|| = √((60√3)² + (-40)²) N = 20√31 N
and its direction relative to the positive horizontal axis (rightward) is θ such that
tan(θ) = (-40) / (60√3) = -2/(3√3)
⇒ θ = arctan(-2/(3√3)) ≈ -21.05°