Answer:1.5×10 to the power of 17(unit-Hertz/H)
Explanation:V=F×Wavelength
F=V/Wavelength=3×10 to power/2×10 to power of -9=1.5×10 to power of 17
Answer:
Terminal velocity of object = 12.58 m/s
Explanation:
We know that the terminal velocity is attained when drag force and gravitational force are of the same magnitude.
Gravitational force = mg = 80 * 9.8 = 784 N
Drag force = 
Equating both, we have

So v = 12.58 m/s or v = -15.58 m/s ( not possible)
So terminal velocity of object = 12.58 m/s
The force between two parallel wires carrying currents in the same direction is attractive. It is repulsive if the currents are in opposite directions.
Answer:
D. The speed of the combined vehicles is less than the initial speed of the truck.
Explanation:
Ik this is late
Answer:
P = 7500 [W]
Explanation:
First We must use Newton's second law to find the force. Newton's Second Law tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
m = mass = 150 [kg]
a = acceleration = 5 [m/s²]
![F = 150*5\\F = 750 [N]](https://tex.z-dn.net/?f=F%20%3D%20150%2A5%5C%5CF%20%3D%20750%20%5BN%5D)
We know that the work is determined by multiplying the force by the distance, in this way the units of the work are [N*m] which corresponds to 1 Joule [J].
And the power is determined by dividing the work by the time, in this way we have that [J/s] corresponds to 1 [W].
We must convert the speed from kilometers per hour to meters per second.
![36[km/hr]*1000[\frac{m}{1km}]*[\frac{1hr}{3600s} ]=10 [m/s]](https://tex.z-dn.net/?f=36%5Bkm%2Fhr%5D%2A1000%5B%5Cfrac%7Bm%7D%7B1km%7D%5D%2A%5B%5Cfrac%7B1hr%7D%7B3600s%7D%20%5D%3D10%20%5Bm%2Fs%5D)

where:
P = power [W]
F = force = 750 [N]
v = 10 [m/s]
![P = 750*10\\P = 7500 [W]](https://tex.z-dn.net/?f=P%20%3D%20750%2A10%5C%5CP%20%3D%207500%20%5BW%5D)