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Tanya [424]
3 years ago
7

A 20 kg mass is moving at 10 m/s and collides with a stationary 5 kg mass, transferring all its momentum in the collision, what

will the velocity ( in m/s) be for the 5 kg ball after they collide?
Physics
1 answer:
Fudgin [204]3 years ago
3 0

Answer:

v = 40 [m/s].

Explanation:

Linear momentum is defined as the product of mass by Velocity. In this way, by means of the following equation, we can calculate the momentum.

P=m*v\\

where:

m = mass [kg]

v = velocity [m/s]

P =20*10\\P =200 [kg*m/s]

Since all momentum is transferred, we can say that this momentum is equal for the mass of 5 [kg]. In this way, we can determine the speed after the impact.

v = P/m\\v = 200/5\\v = 40 [m/s]

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A 24.0 cm long screwdriver is used as a lever to open a can of paint. If the fulcrum is 0.500 cm away from the end of the screwd
ELEN [110]

The ideal mechanical advantage of the screwdriver is 47

Explanation:

In this problem, the screwdriver acts as a lever.

The Ideal Mechanical Advantage (IMA) of a lever is given by:

IMA=\frac{d_i}{d_o}

where:

d_i is the distance of the point of application of the input force from the fulcrum

d_o is the distance of the output force from the fulcrum

In this problem, we have:

d_o = 0.500 cm, since the fulcrum is 0.500 cm from the end

d_i = 24.0 cm - 0.500 cm = 23.5 cm (the distance between the fulcrum and the point where are we holding the screwdriver)

Substutiting,

IMA=\frac{23.50 cm}{0.50 cm}=47

Learn more about levers here:

brainly.com/question/5352966

#LearnwithBrainly

7 0
3 years ago
A backpack weighs 8.2 newtons and has a mass of 5kg on the moon. What is the strength of the gravity on the moon?
Pavel [41]
Weight is equivalent to the product of the mass of an object and the strength of the gravitational field.

Using:
F = ma

a = 8.2 / 5
a = 1.64 N/kg

The gravitational field strength is equivalent to 1.64 N/kg.
7 0
3 years ago
An ideal transformer has 75 turns in the primary coil and n turns in the secondary coil. a 120 v rms 60hz ac voltage source is c
denpristay [2]

think you messed up the symbol for resistor as resistors are measured in ohms where the symbol used for ohms is Greek omega

solving for average power in secondary coil:

average power =(current rms)^2*resistance⇒with a little algebra:

current rms=(√average power/resistance)

current rms=√160W/10Ω

current rms=4amps.

average power is also equal to current rms*voltage rms

with some algebra we can solve for voltage in the secondary wire:

voltage rms= average power/ current rms

voltage rms= 160W/4A

voltage rms=40Volts

now that we have voltage in the soecondary we can solve for the amount of turns in the secondary: Voltage secondary/voltage primary=number of turns in secondary/ number of turns in primary. using some algerbra we can solve for number of turns in secondary: (Voltage secondary/voltage primary)*number of turns in primary=number of turns in secondary

(40V/120V)*75turns=number of turns in secondary

number of turns in secondary=25turns

4 0
3 years ago
An amount of work W is done on an object of mass m initially at rest, and as result it winds up moving at speed v. Suppose inste
sesenic [268]

Answer:

Explanation:

Given

W amount of work is done on the system such that it acquires v velocity after operation(initial velocity)

According to work energy theorem work done by all the forces is equal to change in kinetic energy of object

W=\frac{1}{2}mv^2---1

where m=mass of object

v=velocity of object

When the object is already have velocity v then the final speed is given by work energy theorem

W=\frac{1}{2}mv_f^2-\frac{1}{2}mv^2-----2

From 1 and 2 we get

\frac{1}{2}mv^2=\frac{1}{2}mv_f^2-\frac{1}{2}mv^2

2\times \frac{1}{2}mv^2=\frac{1}{2}mv_f^2

v_f^2=2v^2

v_f=\sqrt{2}v                

8 0
3 years ago
Keisha analyzes this circuit diagram.
Mazyrski [523]
Component ' W ' is the standard schematic symbol for a switch.

The short line between the two circles can be shown straight,
like it is now, when the switch is 'closed' and current can flow.

Or, it can also be drawn slightly tilted, so it's not touching one
of the circles.  In that case, the switch is 'open', no current can
flow through it, and the whole circuit is shut down.
9 0
4 years ago
Read 2 more answers
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