horizontal distance of home run is 400 ft = 122 m
height of the home run is 3 ft = 0.9 m
now the angle of the hit is 51 degree
now we have equation of trajectory of the motion
solving above two equations we have
now here we will plug in all data
<em>so the ball was hit with speed 35.1 m/s from the ground</em>
Answer:
The magnitude of the electric field at a point equidistant from the lines is
Explanation:
Given that,
Positive charge = 24.00 μC/m
Distance = 4.10 m
We need to calculate the angle
Using formula of angle
We need to calculate the magnitude of the electric field at a point equidistant from the lines
Using formula of electric field
Put the value into the formula
Hence, The magnitude of the electric field at a point equidistant from the lines is
