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sweet-ann [11.9K]

3 years ago

14

What is .6 repeating

1 answer:

Dennis_Churaev [7]3 years ago

8 0

Answer:

Im guessing you mean in fractions, in that case

2/3 = .6 repeating

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Use the following statements to find a compound statement for (p∨q)∧rp∨q)∧r p: 5<-3 q: All vertical angles are congruent. r:

guajiro [1.7K]

Given the compound statement <span>(p∨q)∧r
where: p: 5 < -3
q : All vertical angles are congruent.
r: 4x = 36, then x = 9.

Recall the in logic, '</span>∨' symbolises "or" while '∧' symbolises "and".

Therefore, the compound statement <span>(p∨q)∧r can be written as follows:
Either 5 < -3 or all vertical angles are congruent, and if 4x = 36, then x = 9.
</span>

4 0

4 years ago

Express each logarithm in terms of In 2 and In 5.

Sladkaya [172]

Answer:

$5ln2-3ln5$

$2ln5-ln2$

Step-by-step explanation:

∵ $32=2^{5}$

∵ $125=5^{3}$

∵ $ln\frac{32}{125}=ln\frac{2^{5}}{5^{3}}$

∴ $ln2^{5}-ln5^{3}=5ln2-3ln5$

∵ $12.5=\frac{125}{10}=\frac{25}{2}=\frac{5^{2}}{2}$

∴ $ln12.5=ln\frac{5^{2}}{2}$

∴ $ln5^{2}-ln2=2ln5-ln2$

3 0

3 years ago

The 6th grade class is going on a Field Trip. The Adult to Student ratio is 2:5. If there are a total of 70 people on the Field

Rudik [331]

Answer:I think it 20 adult to 50 kids

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

US consumers are increasingly using debit cards as a substitute for cash and checks. From a sample of 100 consumers, the average

scoray [572]

Answer:

A. Margin of error = 128.79

B. The 99% confidence interval for the population mean is (7661.21, 7918.79).

Step-by-step explanation:

We have to calculate a 99% confidence interval for the mean.

The population standard deviation is know and is σ=500.

The sample mean is M=7790.

The sample size is N=100.

As σ is known, the standard error of the mean (σM) is calculated as:

$\sigma_M=\dfrac{\sigma}{\sqrt{N}}=\dfrac{500}{\sqrt{100}}=\dfrac{500}{10}=50$

The z-value for a 99% confidence interval is z=2.576.

The margin of error (MOE) can be calculated as:

$MOE=z\cdot \sigma_M=2.576 \cdot 50=128.79$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 7790-128.79=7661.21\\\\UL=M+t \cdot s_M = 7790+128.79=7918.79$

The 99% confidence interval for the population mean is (7661.21, 7918.79).

8 0

3 years ago

You invested $20,000 in two accounts paying 7% and 8% annual interest, respectively. If the total interest earned for the year

sasho [114]

Answer:

$7,000 at 7%; $13,000 at 8%

Step-by-step explanation

x: the amount invested at 7%

y: the amount invested at 8%

x + y = 20,000

7%.x + 8%.y = 1,530

⇒ x =7,000

y = 13,000

5 0

3 years ago