Answer:
Physical properties can be observed, described, and measured without changing the material. ... To find the volume of a solid, pour liquid in a graduated cylinder and let a solid object sink in the liquid and measure how much volume is in the solid
The molecular formula :
C₆H₁₄O₃PF
<h3>Further explanation</h3>
Given
39.10% carbon, 7.67% hydrogen, 26.11% oxygen, 16.82% phosphorus, and 10.30% fluorine.
Required
The molecular formula
Solution
mol ratio :
C = 39.1 : 12 = 3.258
H = 7.67 : 1 = 7.67
O = 26.11 : 16 = 1.632
P = 16.82 : 31 = 0.543
F = 10.3 : 19 = 0.542
Divide by 0.542
C = 6
H : 14
O = 3
P = 1
F = 1
The empirical formula :
C₆H₁₄O₃PF
(The empirical formula)n = the molecular formula
(C₆H₁₄O₃PF)=184.1
(6.12+14.1+3.16+31+19)n=184.1
(184)n=184.1
n = 1
It’s really any metal because metals form metallic bonds. They are the only substances which can make metallic bonds. So the answer is A
1.curium ( 1944 Marie and Pierre Curie
<span>2.einsteinium ( Albert Einstein) </span>
<span>3.fermium (1953 Enrico Fermi) </span>
<span>4.mendelevium (1955 Dmitri Mendeleev, who devised first Periodic Table) </span>
<span>5.nobelium ( 1957 Alfred Nobel) </span>
<span>6.niobium (1801 Niobe/ daughter of Tantalus) </span>
<span>7.samarium (1879 Samarski, a Russian engineer) </span>
<span>8.titanium (1791 Greek mythology, Titans, first sons of earth) </span>
<span>9.thorium ( 1819 named after Thor of course !!!:) ) </span>
<span>10.tantalum ( 1802 Tantalus of Greek mythology) pick which ever best that your more into hope this helped you alot:/</span>
<h3>Answer:</h3>
C6H12O6
Explanation:
To find empirical formular you write out the element
Carbon Hydrogen Oxygen
3.96 769 5.28
then u althrough divide by their atomic numbers
3.96÷ 12 769÷1 5.28÷16
=0.33 =769 =0.33
also divide althrough by the lowest number
the lowest number is 0.33 so we use it to divide
0.33÷0.33. 769÷0.33. 0.33÷0.33
= 1 = 2 = 1
empirical formular= CH2O
To find the Molecular formular
Molecular number = molar mass
(CH2O)n = 182
(12+1×2+16)n = 182
30n = 182
n = 6
therefore the Molecular formular is C6H12O6
