Answer:
It should be chloride I am almost positive
Explanation:
Typical Seawater
Chloride (Cl-) 18.980
Sodium (Na+) 10.556
Sulfate (SO42-) 2.649
Magnesium (Mg2+) 1.262
1) 2C₆H₆ + 15O₂ = 6H₂O + 12CO₂
2) n(C₆H₆)/2=n(CO₂)/12
n(CO₂)=6n(C₆H₆)
n(CO₂)=6*12.8 mol = 76.8 mol
From the calculation, the pH of the solution is 4.85.
<h3>What is the pH?</h3>
The pH is defined as the hydrogen ion concentration of the solution. We have the ICE table as;
HA + H2O ⇔ H3O^+ + A^-
I 0.335 0 0
C -x +x +x
E 0.335 - x x x
Ka = 1 * 10^-14/Kb
Ka = 1 * 10^-14/1.8 × 10^–5
Ka = 5.56 * 10^-10
Ka = [H3O^+] [A^-]/[HA]
But [H3O^+] = [A^-] = x
5.56 * 10^-10 = x^2/ 0.335 - x
5.56 * 10^-10(0.335 - x ) = x^2
1.86 * 10^-10 - 5.56 * 10^-10x = x^2
x^2 + 5.56 * 10^-10x - 1.86 * 10^-10 = 0
x=0.000014 M
Now;
pH = -log 0.000014 M
pH = 4.85
Learn more about pH:brainly.com/question/15289741
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Answer: The correct is 0.5 moles.
Explanation:
