Answer:
Vaporization is basically just evaporation which does not require nearly as much heat and happens naturally however when it comes to boiling point this is the point where water has been heated enough to start bubbling and changing state slowly.
Explanation:
Answer:
Here's what I get
Explanation:
3. Molar concentration by formula.

(i) Comparison of molar concentrations
The formula gives a calculated value of 0.5302 mol·L⁻¹.
Dimensional analysis gives a calculated value of 0.1767 mol·L⁻¹.
The first value is three times the second.
It is wrong because the formula assumes that the acid supplies just enough moles of H⁺ to neutralize the OH⁻ from the NaOH.
Instead, I mol of H₃PO₄ provides 3 mol of H⁺, so your calculated concentration is three times the true value.
(ii) When is the formula acceptable?
The formula is acceptable only when the molar ratio of acid to base is 1:1.
Examples are
HCl + NaOH ⟶ NaCl + H₂O
H₂SO₄ + Ca(OH)₂ ⟶ CaSO₄ + 2H₂O
H₃PO₄ + Al(OH)₃ ⟶ AlPO₄ + 3H₂O
When the cool and hot zones of a non luminous flame’s air
control valve is closed, the gas in which will be in placed as first and as it
encounters air as it was in the mouth of the burner, there will be a presence
of incomplete mixing, causing a combustion which would be incomplete and will
also lead to a process that can’t be controlled, resulting to flame that is
cool.
Answer:
1. 389 kJ; 2. 7.5 µg; 3. 6.25 days
Explanation:
1. Energy required
The water is converted directly from a solid to a gas (sublimation).
They don't give us the enthalpy of sublimation, but

The equation for the process is then
Mᵣ: 18.02
46.69 kJ + H₂O(s) ⟶ H₂O(g)
m/g: 150
(a) Moles of water

(b) Heat removed
46.69 kJ will remove 1 mol of ice.

2. Mass of water vapour in the freezer
For this calculation, we can use the Ideal Gas Law — pV = nRT
(a) Moles of water
Data:

V = 5 L
T = (-80 + 273.15) K = 193.15 K
Calculation:

(b) Mass of water

3. Time for removal
You must remove 150 mL of water.
It takes 1 h to remove 1 mL of water.
