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Vinil7 [7]
3 years ago
6

The atomic mass of 12C is 12.000000. Multiply the atomic mass of 12C by its abundance. Report the number to 5 significant digits

.
Chemistry
2 answers:
Anna35 [415]3 years ago
5 0

Answer:

1187.2

Explanation:

Given data:

Atomic mass of C₁₂ = 12.000000.

Multiplication of its abundance and mass = ?

Solution:

The natural abundance of carbon-12 is 98.93%.

98.93 × 12. 000000 = 1187.16

Answer in five significant figures:

1187.2

aleksley [76]3 years ago
3 0

Answer : The average mass of carbon is, 11.872 amu

Explanation : Given,

Atomic mass of C-12 = 12.000000 amu

Natural abundance of C-12 = 98.93 % = 0.9893

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Average mass of carbon = Atomic mass of C-12 × Natural abundance of C-12

Average mass of carbon = 12.000000 × 0.9893

Average mass of carbon = 11.872 amu

Thus, the average mass of carbon is, 11.872 amu

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Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.

<h3>What is the equilibrium constant?</h3>

In a reaction, we can judge using the value of the equilibrium constant weather or not the reaction moves on to completion. If the reaction moves up to completion, it the follows that the value of the equilibrium constant ought to be large.

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Answer:

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Hello.

In this case, we first need to take into account that the density of each metal A and B is computed by dividing the mass over the volume of each metal which is actually computed by substracting the volume of water from the volume of the water and the solid:

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