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Vinil7 [7]
3 years ago
6

The atomic mass of 12C is 12.000000. Multiply the atomic mass of 12C by its abundance. Report the number to 5 significant digits

.
Chemistry
2 answers:
Anna35 [415]3 years ago
5 0

Answer:

1187.2

Explanation:

Given data:

Atomic mass of C₁₂ = 12.000000.

Multiplication of its abundance and mass = ?

Solution:

The natural abundance of carbon-12 is 98.93%.

98.93 × 12. 000000 = 1187.16

Answer in five significant figures:

1187.2

aleksley [76]3 years ago
3 0

Answer : The average mass of carbon is, 11.872 amu

Explanation : Given,

Atomic mass of C-12 = 12.000000 amu

Natural abundance of C-12 = 98.93 % = 0.9893

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Average mass of carbon = Atomic mass of C-12 × Natural abundance of C-12

Average mass of carbon = 12.000000 × 0.9893

Average mass of carbon = 11.872 amu

Thus, the average mass of carbon is, 11.872 amu

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he decomposition of acetaldehyde, CH3CHO, was determined to be a second order reaction with a rate constant of 0.0771 M-1 s-1. I
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Answer:

The concentration is [-1 + sqrt(1+0.11t)]/0.1542 M

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Let the concentration of CH3CHO after selected reaction times be y

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What is the exact mass of one mole of carbon-12 atoms
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3 0
3 years ago
A reaction was performed in which 3.6 g 3.6 g of benzoic acid was reacted with excess methanol to make 1.3 g 1.3 g of methyl ben
Anit [1.1K]

<u>Answer:</u> The percent yield of the reaction is 32.34 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For benzoic acid:</u>

Given mass of benzoic acid = 3.6 g

Molar mass of benzoic acid = 122.12 g/mol

Putting values in equation 1, we get:

\text{Moles of benzoic acid}=\frac{3.6g}{122.12g/mol}=0.0295mol

The chemical equation for the reaction of benzoic acid and methanol is:

\text{Benzoic acid + methanol}\rightarrow \text{methyl benzoate}

By Stoichiometry of the reaction

1 mole of benzoic acid produces 1 mole of methyl benzoate

So, 0.0295 moles of benzoic acid will produce = \frac{1}{1}\times 0.0295=0.108 moles of methyl benzoate

  • Now, calculating the mass of methyl benzoate from equation 1, we get:

Molar mass of methyl benzoate = 136.15 g/mol

Moles of methyl benzoate = 0.0295 moles

Putting values in equation 1, we get:

0.0295mol=\frac{\text{Mass of methyl benzoate}}{136.15g/mol}\\\\\text{Mass of methyl benzoate}=(0.0295mol\times 136.15g/mol)=4.02g

  • To calculate the percentage yield of methyl benzoate, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of methyl benzoate = 1.3 g

Theoretical yield of methyl benzoate = 4.02 g

Putting values in above equation, we get:

\%\text{ yield of methyl benzoate}=\frac{1.3g}{4.02g}\times 100\\\\\% \text{yield of methyl benzoate}=32.34\%

Hence, the percent yield of the reaction is 32.34 %

6 0
3 years ago
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