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Vinil7 [7]
4 years ago
6

The atomic mass of 12C is 12.000000. Multiply the atomic mass of 12C by its abundance. Report the number to 5 significant digits

.
Chemistry
2 answers:
Anna35 [415]4 years ago
5 0

Answer:

1187.2

Explanation:

Given data:

Atomic mass of C₁₂ = 12.000000.

Multiplication of its abundance and mass = ?

Solution:

The natural abundance of carbon-12 is 98.93%.

98.93 × 12. 000000 = 1187.16

Answer in five significant figures:

1187.2

aleksley [76]4 years ago
3 0

Answer : The average mass of carbon is, 11.872 amu

Explanation : Given,

Atomic mass of C-12 = 12.000000 amu

Natural abundance of C-12 = 98.93 % = 0.9893

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Average mass of carbon = Atomic mass of C-12 × Natural abundance of C-12

Average mass of carbon = 12.000000 × 0.9893

Average mass of carbon = 11.872 amu

Thus, the average mass of carbon is, 11.872 amu

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Identify the oxidized substance, the reduced substance, the oxidizing agent, and the reducing agent in the redox reaction. Cu(s)
spin [16.1K]

<u>Answer:</u> Copper is getting oxidized and is a reducing agent. Silver is getting reduced and is oxidizing agent.

<u>Explanation:</u>

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the reaction in which an atom gains electrons. Here, the oxidation state of the atom decreases.

X^{n+}+ne^-\rightarrow X

Oxidizing agents are defined as the agents which oxidize other substance and itself gets reduced. These agents undergoes reduction reactions.

Reducing agents are defined as the agents which reduces the other substance and itself gets oxidized. These agents undergoes reduction reactions.

For the given chemical reaction:

Cu(s)+2AgNO_3(aq.)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq.)

The half reactions for the above reaction are:

<u>Oxidation half reaction:</u>  Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-

<u>Reduction half reaction:</u>  2Ag^+(aq.)+2e^-\rightarrow 2Ag(s)

From the above reactions, copper is loosing its electrons. Thus, it is getting oxidized and is considered as a reducing agent.

Silver is gaining electrons and thus is getting reduced and is considered as an oxidizing agent.

4 0
4 years ago
Pliss help
Vladimir [108]

Answer: I believe it is artificial selection (not certain though)

Explanation: modern day dogs have been bread an domesticated to be used by humans in ways we see fit.

5 0
3 years ago
What is the sum of the coefficients of the balanced equation for:
Marianna [84]

Answer:

3 Pb(NO3)2 + Al2(SO4)3 = 2 Al(NO3)3 + 3 PbSO4

Explanation:

I think your equation is incorrect? This is balanced and the sum of coefficients is 9.

5 0
3 years ago
At a temperature of 393 K, the pressure of a sample of nitrogen is 1.07 atm. What will the pressure be at a temperature of 478 K
Rainbow [258]

Answer:

1.30atm

Explanation:

P1/T1 = P2/T2

1.07/393 = P2/478

6 0
4 years ago
The solubility of solid W in water is: 1.72 g/100 mL at 0°C, 21.3/100 mL at 100°C. a) How many mL of boiling water are required
grandymaker [24]

Answer:

a) Mass of solid W crystallized out 0°C is 141.564 g

b) 91.92% is the percent recovery.

Explanation:

The solubility of solid W in water at 100°C = 21.3 g/100 mL

Volume of water at 100C required to dissolve 154.0 g of W: x

\frac{154.0 g}{x}=\frac{21.3 g}{100 mL}

x=\frac{154.0 g\times 100 mL}{21.3 g}=723.0 mL

723.0 mL of water will dissolve 154.0 grams of solid W.

The solubility of solid W in water at 0°C = 1.72 g/100 mL

Mass of W soluble in 723.00 mL of water at  0°C = m

\frac{m}{723.0 mL}=\frac{1.72 g}{100 mL}

m=\frac{1.72 g\times 723.0 mL}{100 mL}=12.436 g

a) Mass of solid W crystallized out 0°C : 154.0 g- 12.436 g=141.564 g

b)  Percent recovery of solid at 0°C:

\frac{141.564 g}{154.0 g}\times 100=91.92\%

91.92% is the percent recovery.

5 0
3 years ago
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