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Vinil7 [7]
4 years ago
6

The atomic mass of 12C is 12.000000. Multiply the atomic mass of 12C by its abundance. Report the number to 5 significant digits

.
Chemistry
2 answers:
Anna35 [415]4 years ago
5 0

Answer:

1187.2

Explanation:

Given data:

Atomic mass of C₁₂ = 12.000000.

Multiplication of its abundance and mass = ?

Solution:

The natural abundance of carbon-12 is 98.93%.

98.93 × 12. 000000 = 1187.16

Answer in five significant figures:

1187.2

aleksley [76]4 years ago
3 0

Answer : The average mass of carbon is, 11.872 amu

Explanation : Given,

Atomic mass of C-12 = 12.000000 amu

Natural abundance of C-12 = 98.93 % = 0.9893

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Average mass of carbon = Atomic mass of C-12 × Natural abundance of C-12

Average mass of carbon = 12.000000 × 0.9893

Average mass of carbon = 11.872 amu

Thus, the average mass of carbon is, 11.872 amu

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Because diffusion<span> is the process when molecules move to lower or higher concentration, so as the molecules move faster they are going to lower or high concentration faster.</span>
3 0
3 years ago
The analysis of a compound gives the following percent composition by mass: C: 52.14 percent; H: 9.946 percent; S: 12.66 percent
wariber [46]

Answer:

C11H25SO4

Explanation:

The total mass of the compound is 253.4 g, so, the mass of each element will be:

C: 52.14% of 253.4 = 0.5214x253.4 = 132.12 g

H: 9.946% of 253.4 = 0.09946x253.4 = 25.20 g

S: 12.66% of 253.4 = 0.1266x253.4 = 32.08 g

O: 25.26% of 253.4 = 0.2526x253.4 = 64.00 g

The molar mass are: C = 12 g/mol, H 1 g/mol, S = 32 g/mol, and O = 16 g/mol

So, to know how much moles will be, just divide the mass calculated above for the molar mass:

C: 132.12/12 = 11 moles

H: 25.20/ 1 = 25 moles

S: 32.08/32 = 1 mol

O: 64.00/16 = 4 moles

So the molecular formula is C11H25SO4

3 0
3 years ago
Which gas law would apply to the following scenario.
chubhunter [2.5K]
The ansewer is Boyle’s law
4 0
3 years ago
In this chemical Formula for Ammonia, the Subscripts indicate what?
zubka84 [21]

Answer:

B

Explanation:

B. There are two atoms of Nitrogen and two atoms of Hydrogen combined to make Ammonia.

7 0
3 years ago
Write the overall, balanced molecular equation and indicate which element is oxidized and which is reduced for the following rea
REY [17]

Explanation:

Mg(s) + Cr(C2H3O2)3 (aq)

Overall, balanced molecular equation

Mg(s) + Cr(C2H3O2)3(aq) --> Mg(C2H3O2)3(aq) + Cr(s)

To identify if an element has been reduced or oxidized, the oxidation number is observed in both the reactant and product phase.

An increase in oxidation number denotes that the element has been oxidized.

A decrease in oxidation number denotes that the element has been reduced.

Oxidation number of Mg:

Reactant - 0

Product - +3

Oxidation number of Cr:

Reactant - +3

Product - 0

Note: C2H3O2 is actually acetate ion; CH3COO- The oxidatioon number of C, H and O do not change.

Oxidized : Mg

Reduced : Cr

7 0
3 years ago
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