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ArbitrLikvidat [17]
3 years ago
12

Five mineral samples of equal mass of calcite, caco3 (mm 100.085) , had a total mass of 10.9 ± 0.1 g. what is the average mass o

f calcium in each sample? (assume that the relative uncertainties in atomic mass are small compared the uncertainty of the total mass.)
Chemistry
1 answer:
g100num [7]3 years ago
6 0

The molecular mass of calcite is 100.085 (given).

Atomic mass of calcium = 40.078 amu

Percent amount of calcium in calcite = \frac{40.078}{100.085}\times 100 = 40.044%

The total mass of five mineral samples = 10.9\pm 0.1 g  (given)

So, the mass of one sample = \frac{10.9}{5} = 2.18 g

and \frac{0.1}{5} = 0.02 g

The average mass of calcium in sample = \frac{2.18 g\times 40.044}{100} = 0.873 g

and \frac{0.02 g\times 40.044}{100} = 0.008 g

Hence, the average mass of calcium in each sample is 0.873 g\pm 0.008 g.

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