Explanation:
wanna know why my mom seems to rather- dislike me?- i mean like is it horomonal issues or whatever?! ;_; im confus3d here. can this be counted for a science question?- im not sure. its 12:00AM rn and im actually confused as if this is science or just me wondering the m0st random thingalings. :'D
The original radioisotope underwent double-alpha decay, where the original nucleus lost a total of 4 protons and 4 neutrons.
The original radioisotope would have an atomic number of 86+4 (protons), and would have an atomic mass of 222+8 (protons + neutrons). This would make the element Thorium-230, or 90Th230.
Answer:
The substance can be best classified as a molecular substance
Explanation:
The given information are;
The physical state of the substance at 25°C = Solid state
The physical state of the substance at 150°C = Molten
Molecular substances are those with bonds formed by electron sharing among the constituent atoms and they contain a few number of atoms per molecule. Molecular compounds with molecular weight less than 100, usually exist as liquids or gases at room temperature, while those with molecular weights over 100 can be found in a solid state at room temperature.
Generally, molecular compounds are usually volatile and have a melting point less than 300°C
Therefore, the substance can be best classified as a molecular substance.
Answer: a) 211 mm Hg
b) 0.629 grams
Explanation:
According to Dalton's law, the total pressure is the sum of individual pressures.
![p_{total}=p_1+p_2+p_3+p_4](https://tex.z-dn.net/?f=p_%7Btotal%7D%3Dp_1%2Bp_2%2Bp_3%2Bp_4)
= total pressure = 750 mmHg
= 124 mm Hg
= 218 mm Hg
= 197 mm Hg
= ?
![750 mmHg=124 mm Hg+218 mm Hg+197 mm Hg+p_{He}](https://tex.z-dn.net/?f=750%20mmHg%3D124%20mm%20Hg%2B218%20mm%20Hg%2B197%20mm%20Hg%2Bp_%7BHe%7D)
![p_{He}=211mmHg](https://tex.z-dn.net/?f=p_%7BHe%7D%3D211mmHg)
Thus the partial pressure of the helium gas is 211 mmHg.
b) According to the ideal gas equation:
P = Pressure of the gas = 211 mmHg = 0.28 atm (760mmHg=1atm)
V= Volume of the gas = 13.0 L
T= Temperature of the gas = 282 K
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas= ?
Mass of helium= ![moles\times {\text {molar mass}}=0.157\times 4=0.629g](https://tex.z-dn.net/?f=moles%5Ctimes%20%7B%5Ctext%20%7Bmolar%20mass%7D%7D%3D0.157%5Ctimes%204%3D0.629g)
Thus mass of helium gas present in a 13.0-L sample of this mixture at 282 K is 0.629 grams
Answer pls,.,.,,.,.,.,..;;.;.,.,.,.,..,.,,
Tatiana [17]
Answer:
I don't know exactly but I am pretty sure it's 60.65