2H2 + O2 = 2H2O
i call it water formation?
<span>A </span>flexible container<span> at an </span>initial volume<span> of 7.14 </span>L contains<span> 7.51 </span>mol<span> of </span>gas<span>. </span>More gas<span> is</span>then added<span> to the </span>container until<span> it </span>reaches<span> a </span>final volume<span> of 17.7 </span>L<span>. </span>Assuming<span> the </span>pressure<span> and</span>temperature<span> of the </span>gas remain constant<span>, </span>calculate<span> the </span>number<span> of </span>moles<span> of </span>gas added<span> to the </span>container<span>.</span>
C. Visible light does not produce transitions between electronic energy levels in the N₂ molecule but does produce transitions in the I₂ molecule.
Explanation:
Abortion of light by molecules will produce electronic transitions from a ground level to a higher level equal to the energy of absorbed light.
In the case of nitrogen (N₂) the allowed electronic transitions are between electronic energy levels with a energy difference equal to the energy of photons of the ultraviolet light. Nitrogen will not absorb from the visible range so it is colorless.
Now iodine (I₂) have the allowed electronic transitions between electronic energy levels with a energy difference equal to the energy of photons of the visible light. As a consequence Iodine vapors have a violet color.
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electronic transitions
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Answer:
Explanation:
KHT is a salt which ionises in water as follows
KHT ⇄ K⁺ + HT⁻
Solubility product Kw= [ K⁺ ] [ HT⁻ ]
product of concentration of K⁺ and HT⁻ in water
In KCl solution , the solubility product of KHT will be decreased .
In KCl solution , there is already presence of K⁺ ion in the solution . So
in the equation
[ K⁺ ] [ HT⁻ ] = constant
when K⁺ increases [ HT⁻ ] decreases . Hence less of KHT dissociates due to which its solubility decreases . It is called common ion effect . It is so because here the presence of common ion that is K⁺ in both salt to be dissolved and in solvent , results in decrease of solubility of the salt .
Answer:
τ = - (8.1 N-m) i - (10.8 N-m) j - (8.1 N-m) k
Explanation:
Given
r = (0 m) i + (0.9 m) j - (1.2 m) k
F = (9 N) i + (0 N) j - (9 N) k
We can apply
τ = r x F
τ = ((0 m) i + (0.9 m) j - (1.2 m) k) x ((9 N) i + (0 N) j - (9 N) k)
⇒ τ = - (8.1 N-m) i - (10.8 N-m) j - (8.1 N-m) k
