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kap26 [50]
3 years ago
5

A meter stick is held vertically with one end on the floor and is then allowed to fall. Find the speed of the other end just bef

ore it hits the floor, assuming that the end on the floor does not slip. (Hint: Consider the stick to be a thin rod and use the conservation of energy principle.) Number Enter your answer in accordance to the question statement Units Choose the answer from the menu in accordance to the question statement
Physics
1 answer:
stich3 [128]3 years ago
7 0

Answer:

  v =  7.67 m/s  for L= 1m

Explanation:

Let's use the conservation of mechanical energy, at the highest point and the lowest point

Initial. Vertical ruler

       Em₀ = mg h

Final. Just before touching the floor

       Em_{f} = K = ½ I w²

      Em₀ = Em_{f}

      m g h = ½ I w²

The moment of inertia of a ruler that turns on one end is

      I = 1/3 m L²

Let's replace

      m g h = ½ (1/3 m L²) w²2

      g h = 1/6 L² w²

They ask for the speed of the end so the height h is equal to the length of the ruler

      g L = 1/6 L² w²

The linear and angular variables are related

      v = w r

     w = v / r

In this case the point of interest a in strangers r = L

     g L = 1/6 L² v² / L²

     v = √ 6 g L

Let's calculate

Assume that the length of the meter is L = 1 m

    v = √ (6 9.8 1)

   v =  7.67 m/s

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C.) 1.5 kg

Explanation:

Start with the equation:

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C.) 1.5 kg

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2 years ago
A college dorm room measures 14 ft wide by 13 ft long by 6 ft high. What is the air in it under normal conditions?
kirza4 [7]

Complete question:

A college dormitory room measures 14 ft wide by 13 ft long by 6 ft high. Weight density of air is 0.07 lbs/ft3. What is the weight of air in it under normal conditions?

Answer:

the weight of the air is 76.44 lbs

Explanation:

Given;

dimension of the dormitory, = 14 ft by 13 ft by 6 ft

density of the air, = 0.07 lbs/ft³

The volume of the air in the dormitory room = 14 ft x 13 ft x 6 ft

                                                                          = 1092 ft³

The weight of the air = density  x  volume

                                   = 0.07 lbs/ft³  x  1092 ft³

                                   = 76.44 lbs

Therefore, the weight of the air is 76.44 lbs

6 0
2 years ago
John is traveling north at 20 meters/second and his friend Betty is traveling south at 20 meters/second. If north is the positiv
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Two objects have a force of gravity of 100 N. If the distance between both objects decreases by a factor of 7, while the masses
Shkiper50 [21]

The gravitational force <em>F</em> between two masses <em>M</em> and <em>m</em> a distance <em>r</em> apart is

<em>F</em> = <em>G M m</em> / <em>r</em> ²

Decrease the distance by a factor of 7 by replacing <em>r</em> with <em>r</em> / 7, and decrease both masses by a factor of 8 by replacing <em>M</em> and <em>m</em> with <em>M</em> / 8 and <em>m</em> / 8, respectively. Then the new force <em>F*</em> is

<em>F*</em> = <em>G </em>(<em>M</em> / 8) (<em>m</em> / 8) / (<em>r</em> / 7)²

<em>F*</em> = (1/64 × <em>G M m</em>) / (1/49 × <em>r</em> ²)

<em>F*</em> = 49/64 × <em>G M m</em> / <em>r</em> ²

In other words, the new force is scaled down by a factor of 49/64 ≈ 0.7656, so the new force has magnitude approx. 76.56 N.

8 0
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