Answer:
The speed of the car after the break was applied is 90.46 m/s
Explanation:
Given;
initial velocity of the car, u = 26.8 m/s
accelertation of the car, a = -8.2 m/s²
time of motion, t = 14.3 s
final velocity, v = ?
Apply the following kinematic equation;
v = u + at
v = 26.8 + (-8.2 x 14.3)
v = 26.8 - 117.26
v = -90.46 m/s
magnitude of the final velocity = 90.46 m/s
Therefore, the speed of the car after the break was applied is 90.46 m/s
Answer:
The fraction of kinetic energy lost in the collision in term of the initial energy is 0.49.
Explanation:
As the final and initial velocities are known it is possible then the kinetic energy is possible to calculate for each instant.
By definition, the kinetic energy is:
k = 0.5*mV^2
Expressing the initial and final kinetic energy for cars A and B:


Since the masses are equals:

For the known velocities, the kinetics energies result:




The lost energy in the collision is the difference between the initial and final kinectic energies:


Finally the relation between the lost and the initial kinetic energy:


Suppose earth is a soid sphere which will attract the body towards its centre.So, acc. to law of gravitation force on the body will be,
F=G*m1m2/R^2
but we now that F=ma
and here accleration(a)=accleration due to gravity(g),so
force applied by earth on will also be mg
replace above F in formula by mg and solve,
F=G*mE*m/R^2 ( here mE is mass of earth and m is mass of body)
mg=G*mEm/R^2
so,
g =G*mE/R^2
Velocity, unlike speed, includes a direction.
Velocity is a vector quantity which is defined by magnitude and direction.
Speed is a scalar quantity. It is the rate at which an object moves regardless of which direction.