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Allushta [10]
3 years ago
12

Evaluate the final kinetic energy of the supply spacecraft for the actual tractor beam force, F(x)=αx3+βF(x)=αx3+β.

Physics
1 answer:
Elan Coil [88]3 years ago
8 0

Answer:

K = 1.525 10⁻⁹ x⁴ + 4.1 10⁶ x

Explanation:

To find the variation of kinetic energy, let's use the work energy theorem

            W = ΔK

           ∫ F .dx = K -K₀

If the body starts from rest K₀ = 0

           ∫ F dx cos θ = K

Since the force and displacement are in the same direction, the angle is zero, so the cosine is 1

we substitute  and integrate

          α ∫ x³ dx + β ∫ dx = K

          α x⁴ / 4 + β x / 1 = K

we evaluate from the lower limit F = 0 to the upper limit F

         α (x⁴ / 4 -0) + β (x -0) = K

        K = αX⁴ / 4 + β x

        K = 1.525 10⁻⁹ x⁴ + 4.1 10⁶ x

in order to finish the calculation we must know the displacement

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Answer:

Explanation:

Given

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using equation of motion

v^2-u^2=2as

where v=Final velocity

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a=5\times 10^{16}\ m/s^2

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Acar accelerates from 4 meters/second to 16 meters/second in 4 seconds. The car's acceleration is
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Okay, so we now know what acceleration is. What are its units? The unit of acceleration is the change in velocity over a period of time: \frac{∆v}{t}

If you haven't learned about velocity yet, just think about it as speed for now. The funny-looking triangle, ∆, is a symbol for "the change of." For example, if I started walking at 3 \frac{feet}{second} then sped up to 5 \frac{feet}{second}, then the change in my speed would be 2 \frac{feet}{second}, because I started walking 2 \frac{feet}{second} faster!

Okay, enough with all the explanations. Hopefully, you understand the units now. Let's take a look at the question. A car accelerates from 4 \frac{meters}{second} to 16 \frac{meters}{second}  in 4 seconds. What would the acceleration be? Let's set up an equation:

a = \frac{∆v}{t}

a is the acceleration, ∆v is the change in velocity, and t is the time elapsed.

Now, let's plug in our values! ∆v is the change in velocity, and to find that we simply have to subtract 16 \frac{meters}{second} by 4 \frac{meters}{second}. That makes sense, right? Back to the equation.

a = \frac{∆v}{t}
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(16 - 4 is the change in velocity, and 4 is the number of seconds the car was accelerating)

a = \frac{12}{4}

a = 3 (\frac{meters}{second^{2}})

We have our answer! The car's acceleration is 3 meters per second^{2}.

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Let me know if you need clarification on anything I explained here!
- breezyツ

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