To solve this problem we will apply the concepts related to the Force of gravity given by Newton's second law (which defines the weight of an object) and at the same time we will apply the Hooke relation that talks about the strength of a body in a system with spring.
The extension of the spring due to the weight of the object on Earth is 0.3m, then


The extension of the spring due to the weight of the object on Moon is a value of
, then

Recall that gravity on the moon is a sixth of Earth's gravity.




We have that the displacement at the earth was
, then


Therefore the displacement of the mass on the spring on Moon is 0.05m
The gravitational acceleration of a planet is proportional to the planet's mass, and inversely proportional to square of the planet's radius.
So when you stand on the surface of this particular planet, you feel a force of gravity that is
(1/2) / (3²)
of the force that you feel on the surface of the Earth.
That's <em>(1/18)</em> as much as on Earth.
The acceleration of gravity there would be about <em>0.545 m/s²</em>.
This is about 12% less than the gravity on Pluto.
Any fracture or system of fractures along which Earth moves is known as a fault.
Answer: b. fault.
The answer is parallel
If the <span>circuits in a car</span> were series, they would go out at the same time.
I hope this helps! :3
Answer:

Explanation:
We know that acceleration is change in velocity over time.


v is the final velocity and u is the initial velocity.
Solve for v.
Multiply both sides by t.

Add u to both sides.
