The part of the Electromagnetic (Light) Spectrum used to see through the dust
2 answers:
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Answer:
The energy is and the wavelength is
for the line in the spectrum of hydrogen that represents the movement of an electron from Bohr orbit with n = 2 to the orbit with n = 5.
<em>In what part of the electromagnetic spectrum do we find this radiation? </em>
In the Ultraviolet part of the electromagnetic spectrum.
Explanation:
The energy of the absorbed photon can be known by the difference in energy between the two states in which the transition is happening (In this case from n = 2 to n = 5):
(1)
The permitted energy for the atom of hydrogen, according with the Bohr's model, is defined as:
(2)
Or it can be expressed in Joules, since
(3)
Where the value represents the energy of the ground state¹ and n is the principal quantum number.
For the case of n = 2:
For the case of n = 5:
Replacing those values in equation (1) it is gotten:
The wavelength can be determined by means of the Rydberg formula:
(4)
Where R is the Rydberg constant, with a value of
For this particular case and
:
So the energy is and the wavelength is
for the line in the spectrum of hydrogen that represents the movement of an electron from Bohr orbit with n = 2 to the orbit with n = 5.
<em>In what part of the electromagnetic spectrum do we find this radiation? </em>
In the Ultraviolet part of the electromagnetic spectrum.
Key terms:
¹Ground state: State of minimum energy.