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marin [14]
3 years ago
10

A 72-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.61 m,

and ends with a speed of 8.5 m/s. How much nonconservative work (in kJ) was done on the boy
Physics
1 answer:
chubhunter [2.5K]3 years ago
8 0

Answer:

2849.98 J

Explanation:

From the question,

Work done by the boy = change Potential energy of the boy + change in kinetic energy of the boy

W = ΔP + ΔK..................... Equation 1

Where W = work done by the boy, ΔP = change in potential energy of the boy, ΔK = Change in kinetic energy of the boy.

But,

ΔP = mgΔh.................... Equation 2

ΔK = 1/2mΔv²................. Equation 3

Where m = mass of the boy, Δh = change in height of the boy, Δv = change in velocity of the boy.

Substitute equation 2 and 3 into equation 1

W = mgΔh+1/2mΔv²................. Equation 4

Given: m = 72 kg, Δh = 1.61 m, Δv = 8.5-1.6 = 6.9 m/s, g = 9.8 m/s²

Substitute into equation 4

W = 72(9.8)(1.61)+1/2(72)(6.9²)

W = 1136.016+1713.96

W = 2849.98 J

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Brilliant_brown [7]

Answer:

7.07 hours

Explanation:

divide the distance by the speed

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6 0
3 years ago
Please explain the method of making electricity from non renewable sources like coal?
Leno4ka [110]
The coal is  urned to heat up water. this produces steam. the steam turns a turbine that turns a generator which provided energy yhat can be transferred into electrisity
7 0
3 years ago
What happens to a light wave when it travels from air into glass?
tino4ka555 [31]
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7 0
3 years ago
Two parallel copper rods supply power to a high-energy experiment, carrying the same current in opposite directions. The rods ar
mart [117]

Answer:

the maximum allowable current is 7302.967  amperl

Explanation:

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200 N = (10)^-7 (2I × I) ÷ 0.08 × 1.5

200 = 3.75 × 10^-6 I^2

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= 7302.967  amperl

Hence, the maximum allowable current is 7302.967  amperl

Basically we applied the above formula

6 0
3 years ago
The answer is 4 but idk how to get it so can somebody please explain how to get it
klemol [59]
How much gravitational potential energy does the block have
when it gets to the top of the ramp ?

      (weight) x (height) = (15 N) x (0.2 m)  =  3 Joules .

If there were no friction, you would only need to do 3 Joules of work
to lift the block from the bottom to the top.

But the question says you actually have to do 4 Joules of work
to get the job done.

Friction stole one of your Joules along the way.

Choice-4 is not the correct one.
Choice-1 is the correct one.

===========================

Notice that the mass of the block is NOT  15 kg , and you
don't have to worry about gravity to answer this question.

The formula for potential energy is  (m)·(g)·(h) .
But (m·g) is just the WEIGHT, and the formula
is actually (weight)·(height).
The question GIVES us the weight of the block . . . 15 N .
So the potential energy at the top is just (15N)·(0.2m) = 3 Joules.
3 0
3 years ago
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