Answer:
16.67 grams of H₂ is generated from the electrolysis of 150 grams of H₂O
Explanation:
Electrolysis is the decomposition of a chemical element under the effect of an electric current. So, electrolysis of water is the process of decomposing the H₂O molecule into separate oxygen and hydrogen gases due to an electric current passing through the water.
The balanced equation of electrolysis of water is:
2 H₂O → O₂ + 2H₂
Being:
then the molar mass of the compounds that participate in the reaction is:
- H₂O: 2*1 g/mole + 16 g/mole= 18 g/mole
- H₂: 2*1 g/mole= 2 g/mole
- O₂: 2*16 g/mole= 32 g/mole
If the following amounts in moles are reacted by stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction):
- H₂O: 2 moles
- H₂: 2 moles
- O₂: 1 mole
the amount of mass, by stoichiometry, that reacts and is produced is:
- H₂O: 2 moles*18 g/mole=36 g
- H₂: 2 moles* 2 g/mole= 4 g
- O₂: 1 mole* 32 g/mole= 32 g
Then you can apply the following rule of three: if by stoichiometry 36 g of H₂O generate 4 g of H₂, 150 g of H₂O how much mass of H₂ will it generate?

mass of H₂= 16.67 grams
<u><em>16.67 grams of H₂ is generated from the electrolysis of 150 grams of H₂O</em></u>
<u><em></em></u>
Answer:between 25 and 40 degrees Fahrenheit
Explanation:
Heat pumps do not operate as efficiently when temperatures drop to between 25 and 40 degrees Fahrenheit for most systems. A heat pump works best when the temperature is above 40. Once outdoor temperatures drop to 40 degrees, heat pumps start losing efficiency, and they consume more energy to do their jobs.
Since a pH of 3 is three numbers higher than a pH of 6, we can find the change in acidity by taking 10 to the third power. The solution with a pH of 3 is 1000 times more acidic than the solution with a pH of 6.
Answer:
588.2 mL
Explanation:
- FeSO₄(aq) + 2KOH(aq) → Fe(OH)₂(s) + K₂SO₄(aq)
First we <u>calculate how many Fe⁺² moles reacted</u>, using the given <em>concentration and volume of FeSO₄ solution</em> (the number of FeSO₄ moles is equal to the number of Fe⁺² moles):
- moles = molarity * volume
- 187 mL * 0.692 M = 129.404 mmol Fe⁺²
Then we convert Fe⁺² moles to KOH moles, using the stoichiometric ratios:
- 129.404 mmol Fe⁺² *
= 258.808 mmol KOH
Finally we<u> calculate the required volume of KOH solution</u>, using <em>the given concentration and the calculated moles</em>:
- volume = moles / molarity
- 258.808 mmol KOH / 0.440 M = 588.2 mL