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larisa [96]
3 years ago
9

Horizontal lines indicating a phase change will be at different temperatures depending on the substance.

Chemistry
2 answers:
fredd [130]3 years ago
4 0

Answer:

true

Explanation:

I just know

ieuehdjrj

GalinKa [24]3 years ago
4 0
Yeah its true your welcome
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Which two particles are found in the nucleus of an atom?
choli [55]
Protons and neutrons are found inside the nucleus
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3 years ago
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The molar mass of vitamin A (C20H30O).
vivado [14]
Molar mass of C:  12.011 g/mol
The equation says C20, which means there are 20 carbon atoms in each molecule of Vitamin A.  So, we multiply 12.011 by 20 to get 240.22 g/mol carbon.

Molar mass of H:  1.0079 g/mol
The equation says C30, which means there are 30 hydrogen atoms in each molecule of Vitamin A. So, we multiply 1.0079 by 30 to get 30.237 g/mol hydrogen.

Molar mass of O: 15.999 g/mol
The equation says O without a number, which means there is only one oxygen atom in each molecule of Vitamin A.  So, we leave O at 15.999 g/mol.

Then, just add it up:
240.22 g/mol C + 30.237 g/mol H + 15.999 g/mol O = 286.456 g/mol C20H30O

So, the molar mass of Vitamin A, C20H30O, is approximately 286.5 g/mol.
4 0
3 years ago
2.0 kg of carbon is heated from 25°C to 55°C, and absorbs 42600 joules of heat in the process.
Marrrta [24]

Answer: c = 710 J/kg°C or 0.71 J/g°C

Explanation: Heat is expressed in the formula Q = mc∆T. Derive to find the specific heat c. So the formula will become c = Q / m∆T

c = Q / m∆T

= 42600 J / 2 kg ( 55°C - 25°C )

= 710 J /kg°C

Or can be expressed by converting kg to g.

c = 0.71 J /g°C

6 0
3 years ago
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Fill in the coefficients that will balance the following reaction:
Alex17521 [72]

Answer:

To balance a reaction, the amount of reactants must be equal to the amount of products, as stated by the Law of Conservation of Matter. It may help you to keep track of  the number of each element in a list as you try to balance. It's not able to be balanced.

3 0
2 years ago
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Consider the reaction: N2(g) 2 O2(g)N2O4(g) Write the equilibrium constant for this reaction in terms of the equilibrium constan
Valentin [98]

Answer : The equilibrium constant for this reaction is, K=\frac{(K_b)^2}{K_a}

Explanation :

The given main chemical reaction is:

N_2(g)+2O_2(g)\rightarrow N_2O_4(g);  K

The intermediate reactions are:

(1) N_2O_4(g)\rightarrow 2NO_2(g);  K_a

(2) \frac{1}{2}N_2(g)+O_2(g)\rightarrow NO_2(g);  K_b

We are reversing reaction 1 and multiplying reaction 2 by 2 and then adding both reaction, we get:

(1) 2NO_2(g)\rightarrow N_2O_4(g);  \frac{1}{K_a}

(2) N_2(g)+2O_2(g)\rightarrow 2NO_2(g);  (K_b)^2

Thus, the equilibrium constant for this reaction will be:

K=\frac{1}{K_a}\times (K_b)^2

K=\frac{(K_b)^2}{K_a}

Thus, the equilibrium constant for this reaction is, K=\frac{(K_b)^2}{K_a}

5 0
3 years ago
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