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irina1246 [14]
3 years ago
7

Drug testing if a person do not use drugs how cam he test positive on hair drug test

Chemistry
1 answer:
Hitman42 [59]3 years ago
7 0

For example, certain medications may influence the results of the test.

Drug test can show the presence of illicit or prescription drugs on hair samples, although the person has not used these drugs.

Some of false positive drug use is because of this medications: antihistamines, decongestants, antibiotics, antidepressants, analgesics and antipsychotics.

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Ava, Inc., issued 7% bonds, dated January 1, with a face amount of $117,200 on January 1, 2016 for an issue price of 106.5. The
natta225 [31]

Complete Question

The complete question is shown on the first uploaded image

Answer:

10a The interest payment on the bond is = $ 8,204

10b The debit to cash for the bond proceeds is = $ 302,000

Explanation:

The explanation is shown on the second uploaded image

8 0
3 years ago
A long chain of hydrocarbon bonded to cooh is a ________ acid.
vodomira [7]
A long chain of hydrocarbon bonded to COOH is a FATTY acid.
6 0
3 years ago
Read 2 more answers
The decomposition of nitrogen dioxide is described by the following chemical equation: Suppose a two-step mechanism is proposed
Mandarinka [93]

Answer:

<u>first step </u>

NO2(g)  ------------------------------------> NO(g) + O(g)

<u>second step</u>

NO2(g) + O(g) -----------------------------> NO(g) + O2(g)

Explanation:

<u>first step </u>

NO2(g)  ------------------------------------> NO(g) + O(g)

<u>second step</u>

NO2(g) + O(g) -----------------------------> NO(g) + O2(g)

8 0
2 years ago
Do sound waves travel best in dense or less dense areas?
velikii [3]
Thus, sound will travel at a slower rate in the denser object. If sound waves of the same energy were passed through a block of wood and a block of steel, which is more dense than the wood, the molecules of the steel would vibrate at a slower rate. Thus, sound passes more quickly through the wood, which is less dense.
3 0
2 years ago
Read 2 more answers
what volume of a 0.149 m potassium hydroxide solution is required to neutralize 17.0 ml of a 0.112 m hydrobromic acid solution?
IgorLugansk [536]

Answer: 12.78ml

Explanation:

Given that:

Volume of KOH Vb = ?

Concentration of KOH Cb = 0.149 m

Volume of HBr Va = 17.0 ml

Concentration of HBr Ca = 0.112 m

The equation is as follows

HBr(aq) + KOH(aq) --> KBr(aq) + H2O(l)

and the mole ratio of HBr to KOH is 1:1 (Na, Number of moles of HBr is 1; while Nb, number of moles of KOH is 1)

Then, to get the volume of a 0.149 m potassium hydroxide solution Vb, apply the formula (Ca x Va)/(Cb x Vb) = Na/Nb

(0.112 x 17.0)/(0.149 x Vb) = 1/1

(1.904)/(0.149Vb) = 1/1

cross multiply

1.904 x 1 = 0.149Vb x 1

1.904 = 0.149Vb

divide both sides by 0.149

1.904/0.149 = 0.149Vb/0.149

12.78ml = Vb

Thus, 12.78 ml of potassium hydroxide solution is required.

5 0
2 years ago
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