Question

In a volcanic eruption, a 2400-kgkg boulder is thrown vertically upward into the air. At its highest point, it suddenly explodes (due to trapped gases) into two fragments, one being three times the mass of the other. The lighter fragment starts out with only horizontal velocity and lands 293 mm directly north of the point of the explosion. Where will the fragment land? Neglect any air resistance.

Answer 1

Answer:

Rh = 97.67 m

Explanation:

given data

mass = 2400 kg

lands = 293 mm

solution

as here boulder is thrown upward so at some point will be hightest so at that velocity will be zero

so we apply here conservation of momentum

0 = m1 × v1 - mh × vh   ...............1

m1 × v1 = mh × vh

$\frac{1}{4}$ × 2400 × v1 = $\frac{3}{4}$ × 2400 × vh

v1 = 3 vh

and

R = speed × time

time = $\frac{293}{v1}$

and

Rh = vh × time

Rh = $\frac{1}{3}$ v1  × $\frac{293}{v1}$  

Rh = 97.67 m