All categories

2 years ago

Can someone please help me

Physics

1 answer:

siniylev [52]2 years ago

6 0

Answer:

M a = (M1 + M2) a = F Newton's Second Law

F = (M2 - M1) g net force on the system

a = (M2 - M1) / (M1 + M2) g

a = (9 - 7) / (9 + 7) g = 2 / 16 * 10.0 m/s^2 = 1.25 m/s^2

You might be interested in

A 782-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satelli

Vadim26 [7]

Answer:

a) v = 5.59x10³ m/s

b) T = 4 h

c) F = 1.92x10³ N

Explanation:

a) We can find the satellite's orbital speed by equating the centripetal force and the gravitation force as follows:

$F_{c} = F_{G}$

$\frac{mv^{2}}{r + h} = \frac{GMm}{(r + h)^{2}}$

$v = \sqrt{\frac{gr^{2}}{r+h}$

Where:

g is the gravity = 9.81 m/s²

r: is the Earth's radius = 6371 km

h: is the satellite's height = r = 6371 km

$v = \sqrt{\frac{gr^{2}}{2r}} = \sqrt{\frac{gr}{2}} = \sqrt{\frac{9.81 m/s^{2}*6.371 \cdot 10^{6} m}{2}} = 5.59 \cdot 10^{3} m/s$

b) The period of its revolution is:

$T = \frac{2\pi}{\omega} = \frac{2\pi (r + h)}{v} = \frac{2\pi (2*6.371 \cdot 10^{6} m)}{5.59 \cdot 10^{3} m/s} = 14322.07 s = 4 h$

c) The gravitational force acting on it is given by:

$F = \frac{GMm}{(r + h)^{2}}$

Where:

M is the Earth's mass = 5.97x10²⁴ kg

m is the satellite's mass = 782 kg

G is the gravitational constant = 6.67x10⁻¹¹ Nm²kg⁻²

$F = \frac{GMm}{(r + h)^{2}} = \frac{6.67 \cdot 10^{-11} Nm^{2}kg^{-2}*5.97 \cdot 10^{24} kg*782 kg}{(2*6.371 \cdot 10^{6} m)^{2}} = 1.92 \cdot 10^{3} N$

I hope it helps you!

3 0

3 years ago

Two insulated wires, each 2.64 m long, are taped together to form a two-wire unit that is 2.64 m long. One wire carries a curren

nikklg [1K]

Answer:

$4.77\ \text{A}$

Explanation:

F = Magnetic force = 4.11 N

$I_n$ = Net current

$I_2$ = Current in one of the wires = 7.68 A

B = Magnetic field = 0.59 T

$\theta$ = Angle between current and magnetic field = $65^{\circ}$

$l$ = Length of wires = 2.64 m

$I$ = Current in the other wire

Magnetic force is given by

$F=I_nlB\sin\theta\\\Rightarrow I_n=\dfrac{F}{lB\sin\theta}\\\Rightarrow I_n=\dfrac{4.11}{2.64\times 0.59 \sin65^{\circ}}\\\Rightarrow I_n=2.91\ \text{A}$

Net current is given by

$I_n=I_2-I\\\Rightarrow I=I_2-I_n\\\Rightarrow I=7.68-2.91\\\Rightarrow I=4.77\ \text{A}$

The current I is $4.77\ \text{A}$ .

8 0

3 years ago

A very long, solid insulating cylinder has radius R; bored along its entire length is a cylindrical hole with radius a. The axis

lawyer [7]

Answer:

The value of the electric field is $E_{net} = \dfrac{r \textbf{b}}{2\epsilon_{0}}$

Explanation:

We know that the electric field inside a solid cylinder at a distance $\textbf{r}$ from the centre is given by

$E = \dfrac{\rho \textbf{r}}{2 \epsilon_{0}}$

Let's consider the cross-section of the cylinder as shown in the figure. Let `O' be the centre of the long solid insulating cylinder having radius 'R'. Also consider that $O'$ be the cetre of the hole of radius 'a' situated at a distance 'b' from 'O'. Given, the volume charge density of the material is 'r'. So, the volume charge density inside the hole will be '-r'. Let's consider 'P' be any arbitrary point inside the hole situated at a distance 's' from $O'$ .

So, the electric field ' $E_{O}$ ' due to the long cylinder at point 'P' is given by

$E_{O} = \dfrac{r \textbf{c}}{2 \epsilon_{0}}$

and the electric field ' $E_{O'}$ 'due to the hole at point 'P' is given by

$E_{O'} = \dfrac{\rho \textbf{s}}{2 \epsilon_{0}}$

So the net electric field ( $E_{net}$ ) inside the hole is given by

$E_{net} = E_{O} - E_{O'} = \dfrac{r}{2\epsilon_{0}}(\textbf{c - s}) = \dfrac{r \textbf{b}}{2\epsilon_{0}}$

5 0

4 years ago

What role does activation energy play in an exothermic reaction?

Nuetrik [128]

Answer A material that decreases the rate of a reaction. The amount of energy that reactants must absorb before a chemical reaction will start also called free energy of activation. What role does activation energy pay in chemical reactions? Activation energy is the energy absorbed before it can start a chemical reaction.

Explanation:

3 0

3 years ago

Serena drops a 5-kg book down the stairwell. What is the book's final velocity vf after it falls

elena55 [62]

Answer:

39.2m/s

Explanation:

Given parameters:

Mass of book = 5kg

Time taken for fall = 4s

Unknown:

Final velocity of the book = ?

Solution:

Serena dropped the book from rest therefore, the initial velocity of the book is 0.

Let us find the appropriate motion equation to solve this problem;

V = U + gt

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity = 9.8m/s²

t is the time taken

Insert the given parameters and solve;

V = 0 + 9.8 x 4 = 39.2m/s

3 0

3 years ago

Can someone please help me ​

Can someone please help me