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expeople1 [14]
3 years ago
8

Accounts for about 70% of the mass-energy content of the universe. It acts in opposition to gravity.

Physics
1 answer:
Talja [164]3 years ago
3 0
I think it’s b because gravity pulls down or tword and that says moving away I could be wrong but I think it’s b
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What is true about resistance? Check all that apply. A. It is the excess accumulation of electric charge B. It is measured in oh
Alekssandra [29.7K]

Answer:

B, C and E

Explanation:

The unit of resistance in the international system is the Ohm, the equation that describes the resistance is:

R=p\frac{l}{S} \\

Where (l) is for lenght of the wire, (S) is the area and (p) its the constant associated to the conductor.

It's related by the Ohm's Law:

R=\frac{V}{I}

3 0
3 years ago
Anyone.... help with this two questions...​
PSYCHO15rus [73]

Answer:

what is the question

]

Explanation:

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7 0
2 years ago
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The graph shows the progress of a car which traveled 300 km in 5 hrs. Assuming that its speed remained constant, how far had the
lisov135 [29]
If the car travels
300 km.........................5 hrs
?km ..............................2h
to find out we do (300*2)/5=600/5=120km
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in 2 hours
120km
6 0
3 years ago
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Fiesta28 [93]

Answer:

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2 years ago
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Oscilloscopes have parallel metal plates inside them to deflect the electron beam. These plates are called the deflecting plates
Alina [70]

Answer:

The capacitance of the deflecting plates is C=1.59 pF.

Explanation:

The expression for the capacitance of the capacitor in terms of area and distance is as follows;

C=\frac{\varepsilon _{0}A}{d}

Here, C is the capacitance, A is the area, d is the distance and \varepsilon _{0} is the absolute permittivity.

Convert the side of the square from cm to m.

s= 3.0 cm

s= 0.030 m

Calculate the area of the square.

A= s_^{2}

Put s= 0.030 m.

A=(0.030)_^{2}

A=9\times10^{-4}m^{-2}

Convert distance from mm to m.

d= 5.0 mm

d=5\times10^{-3}m

Calculate the capacitance of the deflecting plates.

C=\frac{\varepsilon _{0}A}{d}

Put d=5\times10^{-3}m, A=9\times10^{-4}m^{-2} and \varepsilon _{0}=8.85\times 10^{-12}Fm^{-1}.

C=\frac{(8.85\times 10^{-12})(9\times10^{-4})}{5\times10^{-3}}

C=1.59\times 10^{-12}F

C=1.59 pF

Therefore, the capacitance of the deflecting plates is C=1.59 pF.

4 0
3 years ago
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