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Ivan
3 years ago
12

Which motion occurs at a rate of approximately one degree per day?

Physics
2 answers:
timurjin [86]3 years ago
6 0
Earth revolving around the sun occurs at approximately one degree per day
Ainat [17]3 years ago
5 0
-- Earth in its solar orbit

-- the apparent motion of the Sun along the ecliptic
(its annual path through the stars).
You might be interested in
A 200 N resultant force acts on 350 kg object. Calculate how long it takes this force to change the objects velocity from 3 m/s
Zanzabum
5m/s because all you have to do is add 3 and 8
4 0
2 years ago
All neutron stars are things that produce intense gravity. All neutron stars are extremely dense objects. Therefore, all extreme
nika2105 [10]

Answer:

Major term is 'things that provide intense gravity'

Minor term is 'extremely dense objects'

Middle term is 'neutron stars'

Explanation:

  • Major term is given by the predicate part of the conclusion
  • Minor term is given by the subject part of sentence in conclusion
  • Middle term is given by the subject part and not the conclusion

6 0
4 years ago
A 7.0-kilogram cart, A, and a 3.0-kilogram cart, B, are initially held together at rest on a horizontal, frictionless surface. W
7nadin3 [17]
For this problem, we use the conservation of momentum as a solution. Since momentum is mass times velocity, then,

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
where
v₁ and v₂ are initial velocities of cart A and B, respectively
v₁' and v₂' are final velocities of cart A and B, respectively
m₁ and m₂ are masses of cart A and B, respectively

(7 kg)(0 m/s) + (3 kg)(0 m/s) = (7 kg)(v₁') + (3 kg)(6 m/s)
Solving for v₁',
v₁' = -2.57 m/s

<em>Therefore, the speed of cart A is at 2.57 m/s at the direction opposite of cart B.</em>
7 0
4 years ago
Replacing an object attached to a spring with an object having 14 the original mass will change the frequency of oscillation of
Pachacha [2.7K]

Answer:

<em>The frequency changes by a factor of  0.27.</em>

<em></em>

Explanation:

The frequency of an object with mass m attached to a spring is given as

f = \frac{1}{2\pi } \sqrt{\frac{k}{m} }

where f is the frequency

k is the spring constant of the spring

m is the mass of the substance on the spring.

If the mass of the system is increased by 14 means the new frequency becomes

f_{n} = \frac{1}{2\pi } \sqrt{\frac{k}{14m} }

simplifying, we have

f_{n} = \frac{1}{2\pi \sqrt{14} } \sqrt{\frac{k}{m} }

f_{n} = \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }

if we divide this final frequency by the original frequency, we'll have

==> \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }  ÷  \frac{1}{2\pi } \sqrt{\frac{k}{m} }

==> \frac{1}{3.742*2\pi  } \sqrt{\frac{k}{m} }  x  2\pi \sqrt{\frac{m}{k} }

==> 1/3.742 = <em>0.27</em>

7 0
3 years ago
Two vectors A and B are added to give a resultant R. The components of A are Ax = -8.0 units and Ay = 6.0 units and the componen
Georgia [21]

Answer:

<em>10.09 units</em>

Explanation:

For the A

Ax = -8.0 units

Ay = 6.0 units

The resultant vector = Ra = \sqrt{A^2_{x} + A^2_{y}  }

Ra = \sqrt{(-8)^2 + 6^2  } =  10 units

For B

Bx = 1.0 units

By = -1.0 units

The resultant vector = Rb = \sqrt{B^2_{x} + B^2_{y}  }

Rb = \sqrt{1^2 + (-1)^2  } = \sqrt{2} units

Adding these two vectors A and B together, magnitude of vector R is

R = \sqrt{R^2_{a} + R^2_{b}  }

R =  \sqrt{10^2 + (\sqrt{2} ) ^2} = <em>10.09 units</em>

5 0
4 years ago
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