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3 years ago

You push against a wall and the wall pushes back on you.

Physics

1 answer:

emmainna [20.7K]3 years ago

4 0

Answer:

Its the third law of motion.

Explanation:

Newton's third law of motion states that every action has equal and opposite reaction.

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A solid sphere rolling without slipping on a horizontal surface. If the translational speed of the sphere is 2.00 m/s, what is i

koban [17]

Answer:

The total kinetic energy is 2.8m J. (NOTE: m is mass of the sphere)

Explanation:

The total kinetic energy of a sphere is given by the sum of the rotational kinetic energy and the translational kinetic energy. That is,

$K_{Total} = K_{R} + K_{T}$

The rotational kinetic energy $K_{R}$ is given by

$K_{R} = \frac{1}{2}I\omega^{2}$

Where $I$ is the moment of inertia

and $\omega$ is the angular velocity

The translational kinetic energy $K_{T}$ is given by

$K_{T} = \frac{1}{2}mv^{2}$

Where $m$ is the mass

and $v$ is the translational speed (velocity)

∴ $K_{Total} = \frac{1}{2}I\omega^{2} + \frac{1}{2}mv^{2}$

But, the moment of inertia $I$ of a sphere is given by

$I = \frac{2}{5}mr^{2}$

Where $m$ is mass

and $r$ is radius

∴ $K_{Total} = \frac{1}{2}\times \frac{2}{5}mr^{2} \omega^{2} + \frac{1}{2}mv^{2}$

$K_{Total} = \frac{1}{5}mr^{2} \omega^{2} + \frac{1}{2}mv^{2}$

Also, $\omega = \frac{v}{r}$

∴ $\omega^{2} = \frac{v^{2} }{r^{2} }$

Then,

$K_{Total} = \frac{1}{5}mr^{2} \times \frac{v^{2} }{r^{2} } + \frac{1}{2}mv^{2}$

$K_{Total} = \frac{1}{5}mv^{2} + \frac{1}{2}mv^{2}$

∴ $K_{Total} = \frac{7}{10}mv^{2}$

From the question, $v = 2.00 m/s$

Then,

$K_{Total} = \frac{7}{10}m(2.00)^{2}$

$K_{Total} = \frac{7}{10}m\times 4.00$

$K_{Total} = 2.8m J$

Hence, the total kinetic energy is 2.8m J. (NOTE: m is mass of the sphere)

8 0

3 years ago

What will the angle of refraction be for a ray of light passing from air into a sodium chloride crystal if the angle of incidenc

wlad13 [49]

Answer:

<h2> The refracted angle is r= 34.47°</h2>

Explanation:

According to snell's law the incident normal and refracted ray at the point of incidence all lie in the same plane

Given

incident angle i= 60°

refracted angle r= ?

index of refraction u= 1.53.

Applying the formula

$u= \frac{sine (i)}{sine( r)}$

solving for r

$1.53=\frac{ sine (60)}{ sine( r)}\\\1.53= \frac{0.866}{ sine( r)} \\\ sine( r)= \frac{0.866}{1.53} \\\sine(r)= 0.566\\\r= sine^-0.566\\\r= 34.47$

r= 34.47°

3 0

4 years ago

If it takes an amount of work W to move two q point charges from infinity to a distance d apart from each other, then how much w

aleksklad [387]

Answer:3W

If it takes an amount of work W to move two q point charges from infinity to a distance d apart from each other, then how much work should it take to move three q point charges from infinity to a distance d apart from each other?

A) 2W

B) 3W

C) 4W

D) 6W

Explanation: calculating work done,W, in moving two positive q point charges from infinity to a valued distance d from each other is

W = k(+q)(+q)/ d

k is couloumb's constant

work done in moving 3 equal positive charges from infinity to a finite distance is given by

W₂=W₄=W₆=k(+q)(+q)/ d

Total work done, W' =k(+q)(+q)/ d + k(+q)(+q)/ d + k(+q)(+q)/ d

= W + W + W = 3W

7 0

3 years ago

Help me please with this homework

liq [111]

Because each case i observed happened due to the experiments that I did with my partner.

8 0

3 years ago

A rocket is fired upwards with an acceleration of 32 m/s2 . If the 200kg rocket experiences an air resistance force of 12000N, w

shutvik [7]

Answer: 20360 N

<em>If it served you, give me 5 stars please, thank you!</em>

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6 0

3 years ago