After leaving the end of a ski ramp, a ski jumper lands downhill at a point that is displaced 68.3 m horizontally from the end o
1 answer:
Answer:
a)52.58 m/s
b)56.13°
Explanation:
assume the upward direction as positive
x-component of the velocity = 29.3×cos33.6°=24.40 m/s (remain constant)
y-component of the velocity which is -29.3sin33.6°= -16.21 m/s
time of flight = 68.3/24.40= 2.7991 seconds
now, we can obtain final velocity in y-direction
=43.66 m/s
=52.58 m/s
for direction
56.13° from the horizontal
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Answer:
3.16 m·s⁻¹ at an angle of 71.6°
Explanation:
Assume that the diagram is like Fig. 1 below.
The boat is heading straight across the river and the current is directed straight downstream.
We have two vectors at right angles to each other.
1. Calculate the magnitude of the resultant
We can use the Pythagorean theorem (Fig. 2).
R² = (3 m·s⁻¹)² + (1 m·s⁻¹)² = 9 m²·s⁻² + 1 m²·s⁻² = 10 m²·s⁻²
R = √(10 m²·s⁻²) ≈ 3.16 m·s⁻¹
2. Calculate the direction of the resultant
The direction of the resultant is the counterclockwise angle (θ) that it makes with due East .
tanθ = opposite/adjacent = 3/1 = 3
θ = arctan 3 = 71.6°
To an observer at point O, the velocity of the boat is 3.16 m·s⁻¹ at an angle of 71.6°.
