Solution :
Faulty electrical connects = P(A) = 0.80
Mechanical defects = P(B) = 0.92
Mechanical defects are related to loose keys = P(C/B) = 0.27
Improper assembly = P(D/B) = 0.73
Defective wires = P(E/A) = 0.35
Improper connections = P(F/A) = 0.13
Poorly welded wires = P(G/A) = 0.52
Now, the probability due to loose keys = 0.27 x 0.92 = 0.2484
Improperly connected = 0.13 x 0.80 = 0.1040
Poorly welded wires = 0.52 x 0.80 = 0.4160
So, the probability that a failure is due to improperly connected or poorly welded wires = 0.1040 + 0.4160
= 0.5200
If you would like to know how many hours will Lena need to work before she can afford to buy the computer, you can calculate this using the following steps:
$900 - $473 = $427
$427 / $7 = 61 hours of yard work
Result: Lena will need to work 61 hours before she can afford to buy the computer.
Answer:
dependent, 39/155
Step-by-step explanation:
Since the checkers are not replaced, the events are dependent since the number of checkers in the bag when you pick the second time depends on the first pick.
31 checkers—13 red and 18 black.
P(red) = red/ total
= 13/31
Keep the checker
Then 30 checkers—12 red and 18 black.
P(black) = black/ total
= 18/30 = 3/5
P ( red, keep,black) = 13/31 *3/5
39/155
Is this a multiple choice question? If so...what are the options?
