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2 years ago

An object will only change its motion if a force is directly applied to it. is this a true statement?

1 answer:

7 0

True
<span> An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.this is newtons first law</span>

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A block of wood 3 cm on each

djyliett [7]

Answer:

1g/cm3

Explanation:

volume of block is 3 cubed which is 27 cm3

we know density is m/v so d= 27g/27cm3

which is 1g/cm3

if my answer helps please mark as brainliest

7 0

2 years ago

A 500 500500- kg kgstart text, k, g, end text object is accelerating to the right at 10 cm / s 2 10 cm/s 2 10, start text, space

enyata [817]

Given Information:

Mass = m = 500 kg

Acceleration = a = 10 cm/s²

Required Information:

Magnitude of rightward net force = F = ?

Answer:

Magnitude of rightward net force = 50 N

Explanation:

From the Newton's second law of motion

F = ma

Where m is the mass and a is the acceleration

To get force in Newtons first convert 10 cm/s² into m/s²

10/100 = 0.1 m/s²

F = 500*0.1

F = 50 N

Therefore, the magnitude of rightward net force acting on it is 50 Newtons.

8 0

2 years ago

Read 2 more answers

The equation of a transverse wave traveling along a string is 1 1 y (2.00 mm)sin[(20 m )x (600 s )t] − − = − Find the (a) amplit

Lelu [443]

Answer:

a)Amplitude ,A = 2 mm

b)f=95.49 Hz

c)V= 30 m/s ( + x direction )

d) λ = 0.31 m

e)Umax= 1.2 m/s

Explanation:

Given that

$y=2\ mm\ sin[(20m^{-1})x-(600s^{-1})t]$

As we know that standard form of wave equation given as

$y=A sin(\phi -\omega t)$

A= Amplitude

ω=Frequency (rad /s)

t=Time

Φ = Phase difference

$y=2\ mm\ sin[(20m^{-1})x-(600s^{-1})t]$

So from above equation we can say that

Amplitude ,A = 2 mm

Frequency ,ω= 600 rad/s (2πf=ω)

ω= 2πf

f= ω /2π

f= 300/π = 95.49 Hz

K= 20 rad/m

So velocity,V

V= ω /K

V= 600 /20 = 30 m/s ( + x direction )

V = f λ

30 = 95.49 x λ

λ = 0.31 m

We know that speed is the rate of displacement

$U=\dfrac{dy}{dt}$

$U=2\ mm\ sin[(20m^{-1})x-(600s^{-1})t]$

$U=1200\ cos[(20m^{-1})x-(600s^{-1})t]\ mm/s$

The maximum velocity

Umax = 1200 mm/s

Umax= 1.2 m/s

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3 years ago

Why is it good practice for scientists to repeat trails

tensa zangetsu [6.8K]

It makes the data thet they collect more reliable so if they need the data again, they have already tested it a few times so therefor they know that it is right.

8 0

3 years ago

Which of these is an example of a physical change? Question options: wood decaying iron melting paper burning steel rusting

marin [14]

Im pretty sure burning paper

its either that or melting iron but im 90 percent sure its paper burning

4 0

2 years ago