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malfutka [58]
3 years ago
5

What I the Wannnsjsusbevdyx

Physics
2 answers:
Arada [10]3 years ago
3 0
I have no idea what that is, but all of your answers right
Mashutka [201]3 years ago
3 0
#5 is correct. Don't know about #4 because we can't see the question.
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A wire lying along a y axis form y=0 to y=0.25 m carries a current of 2.0 mA in the negative direction of the axis. the wire ful
il63 [147K]

Answer:

1.875*10^-5

Explanation:

8 0
3 years ago
The mass before a reaction is equal to the mass after a reaction? True or false?
diamong [38]

Answer:

\boxed {\boxed {\sf True}}

Explanation:

The Law of Conservation of Mass states that mass cannot be created or destroyed.

So, in a chemical reaction, the mass before a reaction and after cannot be different. In other words, the mass of the products must be equal to the product of the reactants.

So, this is a <u>true statement.</u>

3 0
3 years ago
Expresar 78 458 000 000 en notación científica
alexdok [17]

Answer:

7.8x10^10

Explanation:

divide that value by 10000000000

and you get 7.8

5 0
3 years ago
A car that weighs 1.0 x 10^4 N is initially moving at a speed of 38 km/h when the brakes are applied and the car is brought to a
hram777 [196]

Answer:

Part a) Force on car = 2833.84 Newtons

Part b) Time to stop the car = 3.8 seconds

Part c) Factor for stopping distance is 4.

Part d) Factor for stopping time is 1.

Explanation:

The deceleration produced when the car is brought to rest in 20 meters can be found by third equation of kinematics as

v^2=u^2+2as

where

v = final speed of the car ( = 0 in our case since the car stops)

u = initial speed of the car = 38 km/hr =\frac{38\times 1000}{3600}=10.56m/s

a = deceleration produces

s = distance in which the car stops

Applying the given values we get

0^2=10.56^2+2\times a\times 20\\\\a=\frac{0-10.56^2}{2\times 20}\\\\\therefore a=-2.78m/s^2

Now the force can be obtained using newton's second law as

Force=\frac{Weight}{g}\times a

Applying values we get

Force=\frac{1.0\times 10^4}{9.81}\times -2.78\\\\\therefore F=-2833.84Newtons

The negative direction indicates that the force is opposite to the motion of the object.

Part b)

The time required to stop the car can be found using the first equation of kinematics as

v=u+at with symbols having the same meanings

Applying values we get

0=10.56-2.78\times t\\\\\therefore t=\frac{10.56}{2.78}=3.8seconds

Part c)

From the developed relation of stopping distance we can see that the for same force( Same acceleration) the stopping distance is proportional to the square of the initial speed thus doubling the initial speed increases the stopping distance 4 times.

Part d)

From the relation of stopping time and the initial speed we can see that the stopping distance is proportional initial speed thus if we double the initial speed the stopping time also doubles.

8 0
3 years ago
Occurs when fuel rods produce too much heat
gizmo_the_mogwai [7]
 it is known as the
nuclear meltdown
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