Answer: d. 8.25 m/s
Explanation:
We are given that Current= 5 m/s in j direction
Velocity= 8 m/s i + 3 m/s j
Now, we have to find Jada's speed with respect to the water.
First we find Jada's velocity with respect to water
v= (8 i + 3 j) - (5 j)
v= 8i - 2 j
To find the speed, we take the magnitude of this velocity vector we have
|v|= 
|v|= 
= 8.246 m/s
which comes out to be around = 8.25 m/s
So option d is correct.
Answer:
5 kg
Explanation:
Acceleration = 6 m/s^2
Force = 30 N
Force = mass * acceleration
mass = force / acceleration
mass = 30 / 6
mass = 5 kg
Answer:
False
Explanation:
that is cohesion. adhesion is force between dissimilar molecules of a body
Answer:
It can be replicated and verified.
(c) is correct option.
Explanation:
Given that,
The following statements about a pseudoscientific idea.
(a). It is biased in its results.
(b). It can be tested and observed.
(c). It can be replicated and verified.
(d). It is improved with new information.
We know that,
Pseudo science :
In a pseudoscience, such as statements, trusts and facts about whom it is said these are scientific and logical but these statements is anomalous through the scientific method.
So, we can say that the statement is true about a pseudoscientific idea that is It can be replicated and verified
Hence, It can be replicated and verified.
(c) is correct option.
<span>When the fuel of the rocket is consumed, the acceleration would be zero. However, at this phase the rocket would still be going up until all the forces of gravity would dominate and change the direction of the rocket. We need to calculate two distances, one from the ground until the point where the fuel is consumed and from that point to the point where the gravity would change the direction.
Given:
a = 86 m/s^2
t = 1.7 s
Solution:
d = vi (t) + 0.5 (a) (t^2)
d = (0) (1.7) + 0.5 (86) (1.7)^2
d = 124.27 m
vf = vi + at
vf = 0 + 86 (1.7)
vf = 146.2 m/s (velocity when the fuel is consumed completely)
Then, we calculate the time it takes until it reaches the maximum height.
vf = vi + at
0 = 146.2 + (-9.8) (t)
t = 14.92 s
Then, the second distance
d= vi (t) + 0.5 (a) (t^2)
d = 146.2 (14.92) + 0.5 (-9.8) (14.92^2)
d = 1090.53 m
Then, we determine the maximum altitude:
d1 + d2 = 124.27 m + 1090.53 m = 1214.8 m</span>
